Answer:
The equation of the perpendicular line would be y = -2/5x - 1
Step-by-step explanation:
In order to find this line, we must first find the slope of the original line. We do this by solving for y.
-5x + 2y = -10
2y = 5x - 10
y = 5/2x - 5
This shows us a slope of 5/2. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negative 5/2 to get -5/2 and then we flip it to get -2/5. Now that we have this, we can use the slope and the point in point-slope form to get the equation.
y - y1 = m(x - x1)
y - 1 = -2/5(x + 5)
y - 1 = -2/5x - 2
y = -2/5x - 1
Answer: c) The base is 2.
Reason: It is an exponential function because the variable (2) depends on the x.
I'd say 100 even, don't know if this is a real question or not.
Answer:
<h2><em><u>Option</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>C</u></em></h2>
Step-by-step explanation:
As,
![2 \sqrt{75} + 3 \sqrt{50}](https://tex.z-dn.net/?f=2%20%5Csqrt%7B75%7D%20%20%2B%203%20%5Csqrt%7B50%7D%20)
![= 2 \sqrt{25 \times 3} + 3 \sqrt{25 \times 2} (A)](https://tex.z-dn.net/?f=%20%3D%202%20%5Csqrt%7B25%20%5Ctimes%203%7D%20%20%2B%203%20%5Csqrt%7B25%20%5Ctimes%202%7D%20%28A%29%20)
![= 2 \times 5 \sqrt{3} + 3 \times 5 \sqrt{2}](https://tex.z-dn.net/?f=%20%3D%202%20%5Ctimes%205%20%5Csqrt%7B3%7D%20%20%2B%203%20%5Ctimes%205%20%5Csqrt%7B2%7D%20)
![= 10 \sqrt{3} + 15 \sqrt{2} (C)](https://tex.z-dn.net/?f=%20%3D%2010%20%5Csqrt%7B3%7D%20%20%2B%2015%20%5Csqrt%7B2%7D%20%28C%29)
Answer:
x=101
Step-by-step explanation: