Answer:
The value of AB is
and it's not possible to multiply BA.
Step-by-step explanation:
Consider the provided matrices.
, ![B=\left[\begin{array}{ccc}3\\5\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.
Multiply AB
Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:
![AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
![AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5Ctimes%203%2B3%5Ctimes%205%5C%5C2%5Ctimes%203%2B1%5Ctimes%205%5Cend%7Barray%7D%5Cright%5D)
![AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%2B15%5C%5C6%2B5%5Cend%7Barray%7D%5Cright%5D)
![AB=\left[\begin{array}{ccc}21\\11\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%5C%5C11%5Cend%7Barray%7D%5Cright%5D)
Hence, the value of AB is ![\left[\begin{array}{ccc}21\\11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%5C%5C11%5Cend%7Barray%7D%5Cright%5D)
Now calculate the value of BA as shown:
Multiply BA
Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.
We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.
That means number of column of first matrix should be equal to the number of rows of second matrix.
Hence, it's not possible to multiply BA.
Answer:
Step-by-step explanation:
Let n be a random variable that represents the first Jonathan apple chosen at random that has bitter pit.
a) P(X = n) = q(n-1)p, where q = 1 - p.
From the information given, probability if success, p = 12.6/100 = 0.126
b) for n = 3, the probability value from the geometric probability distribution calculator is
P(n = 3) = 0.096
For n = 5, the probability value from the geometric probability distribution calculator is
P(n = 5) = 0.074
For n = 12, the probability value from the geometric probability distribution calculator is
P(n = 12) = 0.8
c) For n ≥ 5, the probability value from the geometric probability distribution calculator is
P(n ≥ 5) = 0.58
d) the expected number of apples that must be examined to find the first one with bitter pit is the mean.
Mean = 1/p
Mean = 1/0.126 = 7.9
Approximately 8 apples
1 and 3 are odd while 2 and 4 are even. Odd numbers end in 1,3,5,7,9 while even numbers end in 0,2,4,6,8. Please Mark Brainliest!!!
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data below :
x : 89.3 68.6 32.7 37.3 39.7 46.7 66.1 79.4 66.4 52.1 47.3 64.4 53.7 63.4 46.2 63.0 92.1 57.6
Mean(m) = ΣX / n
ΣX = 1066 ; n = number of observations = 18
Mean(m) = 1066 / 18
Mean = 59.22
Standard deviation (σ) :
Using the online standard deviation calculator :
σ = √(Σ(x - m)²/n-1)
σ = √264.198395
σ = 16.72
The mean amount poured into a glass for the 18 samples is 59.22 while the variation in the data samples from the mean value is 16.72.
typical amount poured into a short, wide glass is 19.7 mL. A typical deviation from the mean amount poured is_____mL.
(59.22 - 19.7) mL = 39.52mL
Mean amount poured into a tall slender glass = 51.283
Mean (short wide glass) = 59.22mL
Mean (tall slender glass) = 51.283mL
Short wide glass > tall slender glass