We are given that
Shopkeeper has six coins
total number of coins =6
we know that
there are four types of coins
(1) cents
1 cent =1 cent
(2) nickels
1 nickel =5 cents
(3) dimes
1 dimes =10 cents
(4) quarters
1 quarter = 25 cents
so, we can use trial and error method
Since, nickels , dimes and quarter are multiple of 5
and there 38 cents
so, three coins must be cent
number of cent coins =3
so, the remaining cent = 38-3=35
so, possible coins can be 1 quarter and 2 nickels
1 quarter + 2 nickels =25+2(5)=35
so, coins were
Number of cents =3
Number of nickels =2
Number of dimes =0
Number of quarter =1..................Answer
Answer:
answer: b) x = 3, x = -1
Step-by-step explanation:
3|2x - 2| + 6 = 18.
divid by 3 :
|2x - 2| + 2 = 6
add -2 : |2x - 2| = 4
2x-2=4 or 2x-2=-4
2x=6 or 2x=-2
x=3 or x=-1
Answer:
If:
(1)
And we have to rewrite the following expresion in terms of 
:
(2)
Firstly we have to rearrange the right side of equation (2) in terms of 
, factorizing by the common factor:
Then, we can substitute by :
And set it equal to zero:
>>>>This is the resulting equation
Now, each term of an algebraic expresion (like the equation above) is composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).
In this case, the variable is and the number that multiplies the variable (the coefficient) is 
, whereas the constant (which is the term with no variable) is 
