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Marta_Voda [28]
3 years ago
14

Candy selling at $6.00 per pound will be mixed with candy selling at $9.00 per pound. How many pounds of the more expensive cand

y are needed to produce a 15-pound mixture that sells for $7.00 per pound?
Mathematics
1 answer:
hjlf3 years ago
3 0
The aswer is $1.200 per pound 
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An exponential relationship has a growth factor of3and y-intercept of 4.Evalute the function that represents the function that r
Murrr4er [49]

Answer:

f(10)= 236196

Step-by-step explanation:

Given

(x,y) = (0,4) --- y intercept

b = 3 --- growth factor

Required

f(10)

An exponential function is represented as:

y = ab^x

(x,y) = (0,4) means

4=a * b^0

4=a *1

a= 4

So, we have:

y = ab^x

y = 4(3)^x

or

f(x)= 4(3)^x

When x is 10, the value of the function is:

f(x)= 4(3)^x

f(10)= 4(3)^{10

f(10)= 236196

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3 years ago
a certain star is 4.4x10^2 light years away from the sun one light year is about 5.9x10^12. how far from the earth in miles is t
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Hhhhuhb 457 ygrdc 4430
3 0
3 years ago
What is the measure of angle S?
nevsk [136]

132 + 56 + 79 = 267

360 - 267 = 93

answer is 93 degrees

6 0
3 years ago
A soup can in the shape of a right circular cylinder is to be made from two materials. The material for the side of the can cost
Advocard [28]

Answer:

Radius = 1.12 inches and Height = 4.06 inches

Step-by-step explanation:

A soup can is in the shape of a right circular cylinder.

Let the radius of the can is 'r' and height of the can is 'h'.

It has been given that the can is made up of two materials.

Material used for side of the can costs $0.015 and material used for the lids costs $0.027.

Surface area of the can is represented by

S = 2πr² + 2πrh ( surface area of the lids + surface are of the curved surface)

Now the function that represents the cost to construct the can will be

C = 2πr²(0.027) + 2πrh(0.015)

C = 0.054πr² + 0.03πrh ---------(1)

Volume of the can = Volume of a cylinder = πr²h

16 = πr²h

h=\frac{16}{\pi r^{2}} -------(2)

Now we place the value of h in the equation (1) from equation (2)

C=0.054\pi r^{2}+0.03\pi r(\frac{16}{\pi r^{2}})

C=0.054\pi r^{2}+0.03(\frac{16}{r})

C=0.054\pi r^{2}+(\frac{0.48}{r})

Now we will take the derivative of the cost C with respect to r to get the value of r to get the value to construct the can.

C'=0.108\pi r-(\frac{0.48}{r^{2} })

Now for C' = 0

0.108\pi r-(\frac{0.48}{r^{2} })=0

0.108\pi r=(\frac{0.48}{r^{2} })

r^{3}=\frac{0.48}{0.108\pi }

r³ = 1.415

r = 1.12 inch

and h = \frac{16}{\pi (1.12)^{2}}

h = 4.06 inches

Let's check the whether the cost is minimum or maximum.

We take the second derivative of the function.

C"=0.108+\frac{0.48}{r^{3}} which is positive which represents that for r = 1.12 inch cost to construct the can will be minimum.

Therefore, to minimize the cost of the can dimensions of the can should be

Radius = 1.12 inches and Height = 4.06 inches

5 0
3 years ago
3x + 2y = 9 x - 4y = 4
kherson [118]

Answer:

Enter a problem...

Algebra Examples

Popular Problems Algebra Solve by Substitution 3x-4y=9 , -3x+2y=9

3

x

−

4

y

=

9

,

−

3

x

+

2

y

=

9

Solve for

x

in the first equation.

Tap for more steps...

x

=

3

+

4

y

3

−

3

x

+

2

y

=

9

Replace all occurrences of

x

in

−

3

x

+

2

y

=

9

with

3

+

4

y

3

.

x

=

3

+

4

y

3

−

3

(

3

+

4

y

3

)

+

2

y

=

9

Simplify

−

3

(

3

+

4

y

3

)

+

2

y

.

Tap for more steps...

x

=

3

+

4

y

3

−

9

−

2

y

=

9

Solve for

y

in the second equation.

Tap for fewer steps...

Move all terms not containing

y

to the right side of the equation.

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x

=

3

+

4

y

3

−

2

y

=

18

Divide each term by

−

2

and simplify.

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x

=

3

+

4

y

3

y

=

−

9

Replace all occurrences of

y

in

x

=

3

+

4

y

3

with

−

9

.

x

=

3

+

4

(

−

9

)

3

y

=

−

9

Simplify

3

+

4

(

−

9

)

3

.

Tap for more steps...

x

=

−

9

y

=

−

9

The solution to the system of equations can be represented as a point.

(

−

9

,

−

9

)

The result can be shown in multiple forms.

Point Form:

(

−

9

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Equation Form:

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image of graph

7 0
3 years ago
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