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Assoli18 [71]
3 years ago
6

Join 331 167 1553,pass Moon janta aaoo, not for bad purpose​

Mathematics
2 answers:
denis23 [38]3 years ago
8 0

Answer:

Sussy?!

Step-by-step explanation:

Pretty suspicious.

Vesnalui [34]3 years ago
6 0

Step-by-step explanation:

iiii9oiii hjix high. kkopoooh

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Please someone help!!! The sides of the base of a square right prism are 16 cm each and the height of the prism is 10 cm. what i
LuckyWell [14K]
The surface area is 1152 cm^2
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3 years ago
Identify the property or rule shown by each equation. 9 divided 1 =9 and 33 times 1 =33
kicyunya [14]

identity property=something times one
5 0
3 years ago
Full steps and all reasons, thanks!​
Nataly_w [17]

You can focus on the two sub-triangles ABC and ACD

We know that they are both right triangles, because we're given that AC and BD are perpendicular.

The sides AB and AD are the hypothenuses of these triangles, so we know their length through the pythagorean theorem:

AD^2 = AC^2+CD^2

AB^2 = AC^2+BC^2

But since we're given BC=CD, the expressions for AD and AB are actually the same expression. This proves that AD=AB, and thus that the triangle is isosceles.

8 0
3 years ago
In a group of 31 pupils, 4 play the flute only. 14 play the piano only. 7 play neither instrument. A student is selected at rand
solmaris [256]

Answer:

probability the student plays both instruments is [  \frac{6}{31}  ]

<h2>                         <u>Explanation</u>:</h2>

students who play both instruments = total students - flute players - piano players - students who play neither instruments

students who play both instruments

→ 31 - 4 - 14 - 7

→ 6 students play both instruments.

probability:

<h2>→  \boxed{\frac{students- who -play- both- instruments}{total -students} }</h2><h2>→                     \boxed{\frac{6}{31} }</h2>
7 0
2 years ago
Read 2 more answers
Hi can you help me please?)
AlladinOne [14]

<em>*To solve for a specified variable, you need to isolate that variable onto one side.</em>

<h3>11.</h3>

Firstly, subtract 5r on both sides: 2p=q-5r

Lastly, divide both sides by 2 and <u>your answer will be p=\frac{1}{2}q-\frac{5}{2}r</u>

<h3>12.</h3>

First, subtract z on both sides of the equation: -10-z=xy

Next, divide both sides by y and <u>your answer will be \frac{-10-z}{y}=x</u>

<h3>13.</h3>

Firstly, multiply both sides by b: a=cb

Next, divide both sides by c and <u>your answer will be \frac{a}{c}=b</u>

5 0
3 years ago
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