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Assoli18 [71]
3 years ago
6

Join 331 167 1553,pass Moon janta aaoo, not for bad purpose​

Mathematics
2 answers:
denis23 [38]3 years ago
8 0

Answer:

Sussy?!

Step-by-step explanation:

Pretty suspicious.

Vesnalui [34]3 years ago
6 0

Step-by-step explanation:

iiii9oiii hjix high. kkopoooh

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O graph the equation 2x + 5y = 10, Zeplyn draws a line through the points (5, 0) and (0, 2). What is the slope of the line repre
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2x + 5y = 10
Change to y = mx + b
subtract 2x from both sides
5y = -2x + 10
divide both sides by 5
y = -2/5x + 2
slope = -2/5
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A salesman earned commission of £2 520 for January. His rate of
Free_Kalibri [48]

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I'm sorry but I don't know English so I can't help you

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how do i tell you i don't know english so i can't help you friendy and well, I don't know why it won't let me upload my answer xd

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A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks
klio [65]

Answer:

a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are in favor of making the Tuesday before Thanksgiving a holiday, or they are against. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

So, the binomial probability distribution has two parameters, n and p.

In this problem, we have that n = 1000 and p = \frac{700}{1000} = 0.7. So the parameter is

a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.

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