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il63 [147K]
3 years ago
7

Vincent rolls two dice. What is the probability his results are a multiple of four or the

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer:

Sample space: 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 3.1, 3.2, 3.3, 3.4, 3.5, 3.6, 4.1, 4.2, 4.3, 4.4, 4.5, 4.6, 5.1, 5.2, 5.3, 5.4, 5.5, 5.6, 6.1, 6.2, 6.3, 6.4, 6.5, 6.6.

So the mutiples are 1.3, 2.2, 2.6, 3.1, 3.5, 4.4, 5.3, 6.2, and 6.6

Greather than 6 is 1.6, 2.5, 3.4, 3.6, 4.3, 4.5 4.6, 5.2, 5.4, 5.5, 5.6, 6.1, 6.3, 6.4, and 6.5.

So the prop is 24/36 or 2/3=66%

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Step-by-step explanation:

After a small online search, I've found a table to complete this problem, that we can see below.

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P(Z|B) = probability of Z given that B

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P(Z|B) = P(Z∩B)/P(B)

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So, if the probability of Z given B is different than P(Z) (the probability of event Z) means that the events are not independent.

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In the table we can see:

P(Z|B) will be equal to the quotient between all the cases of Z given B (126) and the total cases are given B (280)

P(Z|B) = 126/280 = 0.45

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And P(Z) = 297/660 = 0.45

So we can see that:

P(Z|B) =  P(Z)

Thus, B and Z are independent.

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