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2 years ago

Find the interest earned.

1 answer:

5 0

September
30-10=20 days
October 31
November 10
Time=20+31+10=61 days
A=42,000×(1+0.035÷365)^(61)
A=42,246.38
Interest earned
I=42,246.38−42,000
I=246.38

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How much is a million grains of salt

mamaluj [8]

It’s a million grains. Duhhhhh

4 0

2 years ago

Can someone please explain what I have to do

Pepsi [2]

Answer:

16.7 cm

Step-by-step explanation:

Area of a triangle = ½*base*height

Area of the shaded region = area of triangle = 100.2 cm³

base = w

height = 12 cm

Plug in the value into the equation:

½*w*12 = 100.2

6w = 100.2

w = 100.2/6

w = 16.7 cm

4 0

2 years ago

Draw and classify the polygon with the given vertices. Find the perimeter and the area of the polygon. M(-2,5), N(3,-2), P(-2,-2

Nadusha1986 [10]

Answer:

Perimeter = 20.6cm to 1dp = 20.60cm to 2dp

Area = Base = 8.6/2 = 4.3 x 4.069 = 17.5cm^2

Height is found 4.07 cos( 54.47deg) 5/8.6 = 4.069cm

Step-by-step explanation:

Right angle side triangle, sides

= MN =8.6cm

= NP=5cm

= PM=7cm

= 25sq + 49sq = 74sq

MN^2 =√74 = 8.60232526704 = 8.6cm

P = 8.6 + 5 + 7 = 20.6cm

5 0

2 years ago

Read 2 more answers

A number divided by 3 with 19 added equals 36 what is the number

julsineya [31]

You do the sum backwards,
36-16=17
17x3=51
Then you check it to make sure,
51/3=17
17+19=36
:) hope this hepled x

7 0

3 years ago

Read 2 more answers

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

2 years ago