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vampirchik [111]
3 years ago
12

Find the nature of roots for equation 2x square -root5x -2 =0 Pls help me fast

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

Answer:

roots are real and distinct

Step-by-step explanation:

To determine the nature of the roots use the discriminant , b² - 4ac

• If b² - 4ac > 0 then 2 real and distinct roots

• If b² - 4ac = 0 then 2 real and equal roots

• If b² - 4ac < 0 then roots are not real

Given

2x² - \sqrt{5} x - 2 = 0

with a = 2, b = - \sqrt{5} , c = - 2 , then

b² - 4ac

= (- \sqrt{5} )² - ( 4 × 2 × - 2)

= 5 - (- 16)

= 5 + 16

= 21

Since b² - 4ac > 0 then the equation has 2 real and distinct roots

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Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2
butalik [34]

To solve this question, we use the factor theorem, and using it, the polynomial function is:

f(x) = x^3 - 2x^2 - 3x + 6

------------------------------

The factor theorem means that if k is a root of f(x), f(k) = 0.

Thus, applying the factor theorem for this question, we have to choose the function for which: f(2) = 0, f(\sqrt{3}) = 0, f(-\sqrt{3}) = 0

------------------------------

Function 1:

f(x) = x^3 - 2x^2 - 3x + 6

Testing the values:

f(2) = 2^3 - 2(2)^2 - 3(2) + 6 = 8 - 8 - 6 + 6 = 0

f(\sqrt{3}) = \sqrt{3^3} - 2(\sqrt{3})^2 - 3\sqrt{3} + 6 = \sqrt{3^2\times3} - 6 - 3\sqrt{3} + 6 = 3\sqrt{3} - 3\sqrt{3} = 0

f(-\sqrt{3}) = -\sqrt{3^3} - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 = -\sqrt{3^2\times3} - 6 + 3\sqrt{3} + 6 = -3\sqrt{3} + 3\sqrt{3} = 0

Thus, since all three conditions are satisfied, f(x) = x^3 - 2x^2 - 3x + 6 is the polynomial function.

A similar question is given at brainly.com/question/11378552

5 0
2 years ago
Jack bought a pair of pants and a shirt for $56. If the price of a shirt is two-fifth of the price of a pair of pants, then what
Juliette [100K]

Answer:

Fraction: 22 2/5  

Decimal: $22.4

Step-by-step explanation:

2/5 x 56

6 0
3 years ago
Read 2 more answers
Point V is located at -16. Points W and X are each 7 units away from Point V. Where are W and X located?
nasty-shy [4]

Answer:

Location of W is - 23, location of X is - 9.

Step-by-step explanation:

location of V = - 16

Points W and X are each 7 units away from Point V.

Let the W is at left of V and X is right of V.

location of W = -16 - 7 = - 23

location of X = - 16 + 7 = - 9

5 0
3 years ago
Write the integer that best represents 23 degrees below zero
snow_tiger [21]
The integer would be -23
5 0
3 years ago
Read 2 more answers
A right triangle has one angle that measure 23o. The adjacent leg measures 27.6 cm and the hypotenuse measures 30 cm.
MrMuchimi

Answer:

161.8cm²

Step-by-step explanation:

solve for height which is the opposite

opp=x

sin(theata)= opp./hyp.

sin23=x/30

x=30×sin23

x=11.72cm

height=opposite

height=11.72cm

base=adjacent

base=27.6cm

½of 27.6cm=13.8

13.8cm×11.72cm=161.74 (2d.p)

161.74 rounded to the nearest tenths= 161.7

I'm not sure if it's the answer but it's the closest thing to the options

4 0
3 years ago
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