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Rashid [163]
3 years ago
7

If f (x) =3 +10 and g(x) =2 - 4, find (f - g) (x)

Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

x=3.22

Step-by-step explanation:

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7x-4 (6-x) +12. if x=6
Darina [25.2K]
We just need to substitute in 6 whether we see an x:

(7*6) - 4*(6-6) + 12
= 42 - 4*0 + 12
=54
4 0
3 years ago
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I need to find how many solutions does the system have. ​
REY [17]
From what I got there is one real solution :)

Rearrange the second equation to give y=2-2x, substitute into the first equation to give you a value for x and then using that you can work out y for the exact coordinates of intersection :)

Also they are both straight line graphs so they will either have one or no solutions

Hope this helped :)
4 0
3 years ago
Please solve my difficult question fast​
kicyunya [14]

The 3 angles form the straight line AB. A straight line equals 180 degrees.

The 3 angles when added together need to equal 180:

2x + 65 + (x + 65) = 180

Simplify by combining like terms:

3x + 130 = 180

Subtract 130 from both sides

3x = 50

Divide both sides by 3

X = 50/3

X = 16 2/3 (16.66667 as a repeating decimal)

Now you have x if you need to solve all the angles replace x with its value and sole:

2x = 2(16 2/3) = 33 1/3

X + 65 = 16 2/3 + 65 = 81 2/3

7 0
2 years ago
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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
2 years ago
The figure below shows half circles at the ends of a rectangle with the demensions shown. Which is closest to the area of the fi
loris [4]
The closest answer is 95 square inches. Here is why.  You can find the area of the rectangle by multiplying the length by the width.  This would be 15 x 5 = 75 square inches.  The area of the whole circle that is created when you put both halves together would be found by multiplying 3.14 x 2.5 in (the radius) x 2.5 in.  This answer is about 20 square inches.  The combined area is approximately 95 square inches.
7 0
3 years ago
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