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krek1111 [17]
3 years ago
8

HELP ASAP!!!! 20PTS

Mathematics
2 answers:
charle [14.2K]3 years ago
6 0

Answer:

m = 36

Step-by-step explanation:

1/3 m+3- 5/6 m=-15

2m+18-5m=-90

-3m+18=-90

-3m=-90-18

-3m=-108

m=36

a_sh-v [17]3 years ago
4 0

Answer:

The answer is m=36

Step-by-step explanation:

2m + 18 - 5m = -90

-3m + 18 = -90

-3m = -90 -18

-3m = -108

m = 36

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Find the exact value of cos(theta) for an angle (theta) with tan (theta)= -2/3 and with its terminal side in Quadrant II.
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Answer:

-\frac{3\sqrt{13}}{13}.

Step-by-step explanation:

Since we are in quadrant two, cosine value is negative while sine value is positive.

We are going to use the Pythagorean Identity: 1+\tan^2(\theta)=\sec^2(\theta).

1+(\frac{-2}{3})^2=\sec^2(\theta)

1+\frac{4}{9}=\sec^2(\theta)

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\frac{13}{9}=\sec^2(\theta)

\pm \sqrt{\frac{13}{9}}=\sec(\theta)

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Since cosine and secant are reciprocals then they will have the same sign as along as they both exist.

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\cos(\theta)=-\frac{3}{\sqrt{13}}.

I don't see this answer as I'm going to rationalize the denominator.

\cos(\theta)=-\frac{3}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}}.

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8 0
4 years ago
Read 2 more answers
What is the factored form of the expression. <br> 4n^2 + 24n + 36
skad [1K]

Answer:

(2n+6)^2

Step-by-step explanation:

To solve this, you can use the given formula: x^2 + 2xy + y^2

In this case, 4n^2 is x^2, 24n is 2xy, and 36 is y^2. The next step is:

(2n)^2 + 2(2n)(6) + (6)^2

Since this equation fits into this formula ( x^2 + 2xy + y^2), we can do:

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Hence, the answer is (2n+6)^2

6 0
3 years ago
Another question (picture)
ASHA 777 [7]


\left( 16 x^8 y^{-12} \right)^{\frac 1 2} = 16^{\frac 1 2} (x^8)^{\frac 1 2} (y^{-12})^{\frac 1 2} = 4 x^4 y^{-6} = \dfrac{4 x^4}{y^6}


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3 years ago
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svp [43]

Answer:

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( ˘ ³˘)/

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Step-by-step explanation:

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