Hello,

$u_{1} =5\\
 u_{2} = u_{1}-6=5-6=-1\\
 u_{3} = u_{2}+7=-1+7=6\\
 u_{4} = u_{3}-6=6-6=0\\
 u_{5} = u_{4}+7=0+7=7\\
 u_{6} = u_{5}-6=7-6=1\\
 u_{7} = u_{6}+7=1+7=8\\
...\\

\boxed{ u_{2n} = u_{2n-1}-6}\\\\

\boxed{ u_{2n+1} = u_{2n}+7}\\

$

7 0

3 years ago

Read 2 more answers

ILL GIVE U BRAINLYIST IF U ANSWER. Find the solution to the system of equations below (you can do this by substitution or elimin

cricket20 [7]

Elimination:

-4x+y=6

-5x-y=21 ...and then u add them together so its;

(the y cancelled out so its 0) x =27

plug in the 27 to any x...

-4(27) + y = 6

-108+y=6

add -108 on both sides so its...

y= -102

(27, -102)

Hope this helped :)

7 0

3 years ago

Find thetwo consecutive integers whose product is 24

malfutka [58]

Answer:

There is no solution to this equation that is an integer for x.

Step-by-step explanation:

x is the first integer, and x+1 the second

$x(x+1) = 24\\x^{2} + x - 24 =0\\$

$x = \frac{-1+\sqrt{1^{2}+4*24}}{2} =\frac{-1+\sqrt{97}}{2}\\x = \frac{-1-\sqrt{1^{2}+4*24}}{2} =\frac{-1-\sqrt{97}}{2}$

5 0

3 years ago

What is Roman numeral of LXVX in number​

What is Roman numeral of LXVX in number