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3 years ago

What’s the answer ??? (ONLY ANSWER IF YOU KNOW)

Mathematics

1 answer:

just olya [345]3 years ago

5 0

First, it says to simplify the expression, so you should try that first.

Simplified Expressions:
8y^15 and 36y^7

Then compare on which simplified expression has the greater exponent
8y^15 and 36y^7
8y^15 has the greater exponent

8y^15 = (y^9)(2y^2)^3 (Or the first expression)

The exponents of expression #1 are greater than the exponents of expression #2

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!

BARSIC [14]

It be 81.

You have to take half of -18 which is -9, and square that, which is 81.

8 0

3 years ago

In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta

Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.3246

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0

3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

6 0

3 years ago

Read 2 more answers

lol Barney has 16 1 yards of fabric. To make an elf costume, he needs 5 5 2 yards of fabric. How many costumes can Barney make?

ioda

Well i happen to have that question and it is that he has 16 1/5 fabric and need 5 2/5 to make an elf costume. how many costumes can he make? Well so basically all you have to do is 16 1/5 divided by 5 2/5, which is: 3. The answer is 3 hope this helped!

7 0

3 years ago

Please answer this correctly

katen-ka-za [31]

Answer:

Step-by-step explanation:

Okay so there is 32 cups in 8 quarts and he sold 6 cups Saturday and 18 cups Sunday.

Add 8+18

Subtract 24-32 to get 8

6 0

3 years ago

Read 2 more answers