Answer:
The potato is 224 feet in the air after 2.75 second on the way up and after 5 seconds on the way back down.
Step-by-step explanation:
Given : A potato launched by a particular potato gun has a height described by
.
To find : When is the potato 224 feet in the air?
Solution :
When the potato is 224 feet in the air i.e. ![h(t)=224](https://tex.z-dn.net/?f=h%28t%29%3D224)
Substitute in the equation
,
![224=-16 t^2+124 t+4](https://tex.z-dn.net/?f=224%3D-16%20t%5E2%2B124%20t%2B4)
![16t^2-124 t+220=0](https://tex.z-dn.net/?f=16t%5E2-124%20t%2B220%3D0)
![4t^2-31t+55=0](https://tex.z-dn.net/?f=4t%5E2-31t%2B55%3D0)
Applying quadratic formula, ![x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Here, a=4, b=-31 and c=55
![t=\frac{-(-31)\pm\sqrt{(-31)^2-4(4)(55)}}{2(4)}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B-%28-31%29%5Cpm%5Csqrt%7B%28-31%29%5E2-4%284%29%2855%29%7D%7D%7B2%284%29%7D)
![t=\frac{31\pm\sqrt{81}}{8}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B31%5Cpm%5Csqrt%7B81%7D%7D%7B8%7D)
![t=\frac{31\pm9}{8}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B31%5Cpm9%7D%7B8%7D)
![t=\frac{31+9}{8},\frac{31-9}{8}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B31%2B9%7D%7B8%7D%2C%5Cfrac%7B31-9%7D%7B8%7D)
![t=5,2.75](https://tex.z-dn.net/?f=t%3D5%2C2.75)
The potato is 224 feet in the air after 2.75 second on the way up and after 5 seconds on the way back down.
Answer:
2
Step-by-step explanation:
When the point on the x-axis is on -3, the point on the y-axis is 2. Therefore, f(-3) is equal to 2.
If this helps please mark as brainliest
Answer:
Radioactive in half life is 51gram
Step-by-step explanation:
80grams:12years
X :7.6years
12x÷x=x
7.6×80÷12=51gram
I think it’a nothing, do you have a bone of the above