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AfilCa [17]
3 years ago
6

Which proportion models this problem?

Mathematics
1 answer:
Ilya [14]3 years ago
7 0
Thank you for posting your question here at brainly. Feel free to ask more questions.  

The best and most correct answer among the choices provided by the question is <span>C. x over 520 = 5 over 13</span>.<span>       
    </span><span>
Hope my answer would be a great help for you.</span>
You might be interested in
<img src="https://tex.z-dn.net/?f=%28-5x%5E3%29%5E3%2F%2810x%5E5%29%5E2" id="TexFormula1" title="(-5x^3)^3/(10x^5)^2" alt="(-5x^
marta [7]

Answer:

-\frac{5}{4x}

Step-by-step explanation:

<h2>\left(-5x^3\right)^3\div \left(10x^5\right)^2</h2><h2>\frac{-5^3x^9}{\left(10x^5\right)^2}</h2><h2>\frac{-5^3x^9}{10^2x^{10}}</h2><h2>\frac{-5^3x^9}{5^2\cdot \:2^2x^{10}}</h2><h2>\frac{-5x^9}{2^2x^{10}}</h2><h2>\frac{-5}{2^2x}</h2>

-\frac{5}{4x}

- hope it helps! -

<h2 />

3 0
2 years ago
Whats 1 added up to 1?
Finger [1]
4 dude lol just playin 2
5 0
2 years ago
WILL GIVE THE BRAINIEST AND 20 POINTS!!!!!!! Find the distance between each pair of points.
salantis [7]

A (5, 4) and B( 5, -2) is 6 units

E(-2, -1) and F(-2, -5) is 4 units

G(3, -5) and H(6, -5) is 3 units

C(-4, 1) and D(1, 1) is 5 units

8 0
3 years ago
Compare the temperature change for the two masses of cold water (50 grams and 100 grams) when the same amount of hot water was a
Vesnalui [34]

Answer:

Step-by-step explanation:

All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature

increase than the 100 gram mass.

Why?

The formula is the same from both masses of water (50 grams and 100 grams)

The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).

We'll leave it on until we see a rise in temperature  delta(t1) = 10 degrees

mc delta(t) = m1 * c * delta(t1)

m = 100

m1 = 50 grams.

c is going to be divided out

we'll solve for the ratio of delta(t) / delta(t1)

100 * delta(t) = 50 (delta(t1)

100 * delta(t) = 50*10

delta(t) = 50*10/100

delta(t) = 5 degrees.

Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.

The 100 gram mass only rises 5 degrees.

The 50   gram mass rises 10 degrees.

7 0
3 years ago
Please help me! Thanks in advance...
adell [148]
Density of water won't change.

and u should not keep it on the table as it cant support its weight which is

w= density*volume = 62*(3*3*3) =1674 lb which is way greater than 200 lb
3 0
4 years ago
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