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3 years ago

How many moles are in 6.02 x 1023 particles of Carbon dioxide?

Chemistry

1 answer:

Rina8888 [55]3 years ago

7 0

Answer:

There is one mole in 6.02*10^23 particles of anything ( also CO2)

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How many hydrogen atoms are in a cycloalkane with 8 carbon atoms?

frosja888 [35]

Cycloalkanes are those saturated organic compounds which exist in the form of Rings. Their Hydrogen Deficiency Index in one. The General formula for cycloalkanes is,
CnH2n
When number of Carbons = 8
Then
C₈H₂₍₈₎

C₈H₁₆

Result:
Cycloalkane containing 8 carbon atoms has 16 hydrogen atoms.

8 0

4 years ago

Consider the titration of 10.00 mL of a monoprotic weak acid with 0.1234 M NaOH. If the equivalence point volume of NaOH was det

gogolik [260]

The initial concentration of the unknown acid is 0.1900 M.

Explanation:

Titration is a chemical method of analysis to know the concentration and volume of the unknown chemical or analyte.

The formula for the titration is:

Macid x Vacid = Mbase x V base

The volume must be in litres. The volume is given in ml it should be divided with 1000 to obtain values in litre.

Data given are:

volume of acid= 10 ml 0.01 L

Molarity of the acid = ?

volume of the NaOH or base = 15.4 ml or 0.0154 L (equivalence point of the base)

molarity of the base = 0.1234 M

Applying the formula and putting the values, we get

Macid x 0.01 = 0.1234 x 0.0154

Macid = 0.1900 M

The weak acid is having molarity of 0.1900 M against the strong base with molarity of 0.1234M.

4 0

3 years ago

Is ice cream matter or nonmatter

fgiga [73]

Answer:

ice cream is matter

fear is non matter (it's a feeling not a physical object)

laptop is matter

noise is non matter

wood is matter

hope this helps :)

4 0

3 years ago

Read 2 more answers

If you know your acid concentration is .650 M and you used 15.00 mL, what was the concentration of the base if you needed 35.5 m

Anvisha [2.4K]

Answer:

0.29

Explanation:

Since the name of the acid (and the equation) is not given, you must assume that it is a 1:1 ratio. Use equation: volume of acid x molarity of acid = volume of base x molarity of base (when the ratio is 1:1).

5 0

4 years ago

A 6.165 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 10.27 grams of CO2 and 3

e-lub [12.9K]

Answer:

Explanation:

mass of carbon in 10.27 g of CO₂ = 12 x 10.27 / 44 = 2.80 g

mass of hydrogen ( H ) in 3.363 g of H₂O = 2 x 3.363 / 18

= .373 g

These masses would have come from the sample of 6.165 g .

Rest of 6.165 g of sample is oxygen .

So oxygen in the sample = 6.165 - ( 2.8 + .373 ) = 2.992 g

Ratio of C , H , O in the sample

2.8 : .373 : 2.992

C: H : O : : 2.8 : .373 : 2.992

Ratio of moles

C: H : O : : 2.8/12 : .373/1 : 2.992 / 16

C: H : O : : .2333 : .373 : .187

C: H : O : : .2333/.187 : .373/.187 : .187/.187

C: H : O : : 1.247 : 1.99 : 1

C: H : O : : 5 : 8 : 4 ( after multiplying by 4 )

Hence empirical formula

C₅H₈O₄

Molecular formula ( C₅H₈O₄ )n

n ( 5 x 12 + 8 x 1 + 4 x 16 ) = 132

n x ( 60 + 8 + 64 ) = 132

n = 1

Molecular formula = C₅H₈O₄.

3 0

3 years ago

How many moles are in 6.02 x 1023 particles of Carbon dioxide? ​

How many moles are in 6.02 x 1023 particles of Carbon dioxide?