Answer:
The pH of the solution is 1.66
Explanation:
Step 1: Data given
Number of moles HCl = 0.022 moles
Molar mass of HCl = 36.46 g/mol
Step 2: Calculate molarity of HCl
Molarity HCl = moles HCl / volume
Molarity HCl = 0.022 moles / 1 L = 0.022 M
[HCl] = [H+] = 0.022 M
Step 3: Calculate pH
pH = -log [H+]
pH = -log(0.022)
pH = 1.66
The pH of the solution is 1.66
Answer:
pH of Buffer Solution 5.69
Explanation:
Mole of anhydrous sodium acetate = 
= 
= 0.18 mole
100 ml of 0.2 molar acetic acid means
= M x V
= 0.2 x 100
= 20 mmol
= 0.02 mole
Using Henderson equation to find pH of Buffer solution
pH = pKa + log![\frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
= 4.74 + log
= 4.74 + log 9
= 5.69
So pH of the Buffer solution = 5.69
Answer:
the fraction of collisions with energy greater than Eact
Explanation:
The activation energy of a reaction stands as a sort of energy barrier between reactants and products. It is only reactants that possesses energy greater than the activation energy that can be converted from reactants to products.
When the temperature of the system is increased, more particles acquire energy greater than the activation energy. Hence, the fraction of collisions with energy greater than the activation energy increases so the rate of reaction increases likewise.
