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3 years ago

2 QUESTIONS: ANSWER THIS with a proper answer plz. PLZ DO NOT ANSWER JUST FOR MY BRAINLY POINTS!!!!

Chemistry

1 answer:

leonid [27]3 years ago

3 0

Answer:

Si hay algo que sucedió entre ustedes raro o un comportamiento que tuviste con esa persona o que te vio hacer asi como le pudieron decir algo de ti que no le gustara a tu amigo hace que se comporte raro contigo

Explanation:

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Which of these are ionic compounds? Check all that apply.

nadezda [96]

The ionic compounds are those where the electronegativity difference between two elements is more than 1.7

Here the following compounds are ionic

A) ammonium chloride : NH₄Cl

D) Rubidium iodide : RbI

And

E) Barium oxide: BaO

3 0

3 years ago

Read 2 more answers

Chapter 7 Ionic Compounds with transition metals. please help!!! will give brainliest

gladu [14]

Answer:

nickle bromide

Ferrous oxide

diFerrous oxide

Tin chloride

lead chloride

tin bromide

chromium phosphoride

ferrous fluoride

gold chloride

tin oxide

3 0

3 years ago

Calculate the amount of heat needed to melt 91.5g of solid benzene ( C6H6 ) and bring it to a temperature of 60.6°C . Round your

Inessa [10]

Answer: The amount of heat required for melting of benzene is 20.38 kJ

Explanation:

The processes involved in the given problem are:

$1.)C_6H_6(s)(5.5^oC)\rightleftharpoons C_6H_6(l)(5.5^oC)\\2.)C_6H_6(l)(5.5^oC)\rightleftharpoons C_6H_6(l)(60.6^oC)$

For process 1:

To calculate the amount of heat required to melt the benzene at its melting point, we use the equation:

$q_1=m\times \Delta H_{fusion}$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of benzene = 91.5 g

$\Delta H_{fusion}$ = enthalpy change for fusion = 127.40 J/g

Putting all the values in above equation, we get:

$q_1=91.5g\times 127.40J/g=11657.1J$

For process 2:

To calculate the amount of heat absorbed at different temperature, we use the equation:

$q_2=m\times C_{p}\times (T_{2}-T_{1})$

where,

$C_{p}$ = specific heat capacity of benzene = 1.73 J/g°C

m = mass of benzene = 91.5 g

$T_2$ = final temperature = 60.6°C

$T_1$ = initial temperature = 5.5°C

Putting values in above equation, we get:

$q_2=91.5\times 1.73J/g^oC\times (60.6-(5.5))^oC\\\\q_2=8722.05J$

Total heat absorbed = $q_1+q_2$

Total heat absorbed = $[11657.1+8722.05]J=20379.2=20.38kJ$

Hence, the amount of heat required for melting of benzene is 20.38 kJ

5 0

3 years ago

1) The hydrocarbon C15 H32 burns to form carbon dioxide and water. Write the equation for the reaction.

Dahasolnce [82]

Explanation:

Ch4+heat=CO2.

Ans

It is not balanced equation if you want it say in comment

8 0

3 years ago

0.0000062 kg in scientific notation

slava [35]

Answer:

6.2 x $10^{-6}$

Explanation:

You are moving the decimal point six spots to the right.

8 0

1 year ago