Given data: <span>molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c.
</span><span>the vapor pressure of pure water at 25 °c is 23.76 mm hg.
</span>Asked: <span>the vapor pressure of a solution made by dissolving 109 grams of glucose
</span><span>
Solution:
moles glucose = 109 g/ 180.2 g/mol=0.605
mass water = 920 mL x 1 g/mL = 920 g
moles water = 920 g/ 18.02 g/mol=51.1
mole fraction water = 51.1 / 51.1 + 0.605 =0.988
vapor pressure solution = 0.988 x 23.76 = 23.47 mm Hg</span>
I think it is with screens l, chemicals, and filters
I hope this helped
In order to calculate the experimental percent error, we follow these steps:
1- Subtract one value from the other (order does not matter as we take absolute)
2- Divide the obtained number by the accepted or true value.
3- Multiply the fraction you got from step 2 by 100 to get the percentage of error.
Now, we will apply these steps on our problem:
1- Subtract one value from the other:
9.95 - 7.13 = 2.82
2- Divide by accepted value:
2.82 / 7.13 = 0.3955
3- Multiply by 100 to get the error percentage:
error percentage = 0.3955 x 100 = 39.55%
Answer: Empirical formula of this compound is 
Explanation:
Mass of Cr= 104.0 g
Mass of O = 48.0 g
Step 1 : convert given masses into moles.
Moles of Cr =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Cr = 
For O =
Converting into simple whole number ratios by multiplying by 2
The ratio of Cr : O= 2: 3
Hence the empirical formula is
The most likely empirical formula of this compound is
