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2 years ago

Helps me solve this problem please

Mathematics

1 answer:

Andre45 [30]2 years ago

4 0

Answer:

The first one

Step-by-step explanation:

I drew it with my graphic calculator.

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Write a simplified polynomial expression in standard form to represent the area of the rectangle below. (2 points) A picture of

Jet001 [13]

Answer:

$Area= 5x^2-18x -8$

Step-by-step explanation:

If the rectangle show one side of length 5 x +2, and another side of length x - 4, then the area of this rectangle (given by the product of the sides' length) is:

$Area = (5x+2)\,(x-4)\\Area = 5x^2-20x+2x-8\\Area= 5x^2-18x -8$

which is already written in standard form.

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3 years ago

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13 Levi bought a new phone for $550. He received a discount of 24%

Likurg_2 [28]

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2 years ago

What is 30 less than 4 times a number is equal to 14

Genrish500 [490]

The answer is x=11
4x-30=14
You add 30 to each side=4x=44
Then you divide 44 by 4 which=11

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3 years ago

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

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3 years ago

3. Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 s

Oxana [17]

Let x be a random variable representing the number of skateboards produced
a.) P(x ≤ 20,555) = P(z ≤ (20,555 - 20,500)/55) = P(z ≤ 1) = 0.84134 = 84.1%

b.) P(x ≥ 20,610) = P(z ≥ (20,610 - 20,500)/55) = P(z ≥ 2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275 = 2.3%

c.) P(x ≤ 20,445) = P(z ≤ (20,445 - 20,500)/55) = P(z ≤ -1) = 1 - P(z ≤ 1) = 1 - 0.84134 = 0.15866 = 15.9%

4 0

3 years ago