<h3>Conner work is correct. Jana work is wrong</h3>
<em><u>Solution:</u></em>
<em><u>Given that,</u></em>
<em><u>Conner and Jana are multiplying:</u></em>
![(3^56^8)(3^96^{10})](https://tex.z-dn.net/?f=%283%5E56%5E8%29%283%5E96%5E%7B10%7D%29)
Given Conner's work is:
![(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}](https://tex.z-dn.net/?f=%283%5E56%5E8%29%283%5E96%5E%7B10%7D%29%20%3D%203%5E%7B5%2B9%7D6%5E%7B8%2B10%7D%20%3D%203%5E%7B14%7D6%5E%7B18%7D)
We have to check if this work is correct
Yes, Conner work is correct
From given,
![(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}](https://tex.z-dn.net/?f=%283%5E56%5E8%29%283%5E96%5E%7B10%7D%29%5C%5C%5C%5C3%5E5%20%5Ctimes%206%5E8%20%5Ctimes%203%5E9%20%5Ctimes%206%5E%7B10%7D)
Use the following law of exponent
![a^m \times a^n = a^{m+n}](https://tex.z-dn.net/?f=a%5Em%20%5Ctimes%20a%5En%20%3D%20a%5E%7Bm%2Bn%7D)
Therefore,
![3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}](https://tex.z-dn.net/?f=3%5E5%20%5Ctimes%206%5E8%20%5Ctimes%203%5E9%20%5Ctimes%206%5E%7B10%7D%20%3D%203%5E5%20%5Ctimes%203%5E9%20%5Ctimes%206%5E8%20%5Ctimes%206%5E%7B10%7D%20%3D%203%5E%7B5%2B9%7D%20%5Ctimes%206%5E%7B8%2B10%7D%20%3D%203%5E%7B14%7D%20%5Ctimes%206%5E%7B18%7D)
<em><u>Given Jana's work is:</u></em>
![(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}](https://tex.z-dn.net/?f=%283%5E56%5E8%29%283%5E96%5E%7B10%7D%29%20%3D%203%5E%7B5.9%7D6%5E%7B8.10%7D%20%3D%203%5E%7B45%7D6%5E%7B80%7D)
This is incorrect
The powers of same base has to be added. But here, powers are multiplied which is wrong
4 doughnuts (Hope that helped)
The y-intercept is (0,-11)
C because The Prime Factorization is: 5 x 5, which is the same thing as 5^2.