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Anna007 [38]
3 years ago
15

If you car was going 60mph and you increased your speed by 5mph every minute for seven consecutive minutes how fast would you be

going at the end
Mathematics
1 answer:
nikklg [1K]3 years ago
7 0
In the end you would be goin 95mph
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What is the probability of rolling a die and it landing on a number less than 3?
snow_tiger [21]

Answer:

2/6 (33.33%)

Step-by-step explanation:

4 0
4 years ago
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The speed of a stream is 4km/h. A boat travels 6 km upstream in the time it takes to travel 12 km downstream. What is the speed
Usimov [2.4K]
<span>6 km × 1 hour/(b-4 km) = 12 km × (1 hour/(b+4 km) 

6/(b-4) hours = 12/(b+4) hours

6(b+4) = 12(b-4)

6b + 24 = 12b - 48
72 = 6b
b = 12 
The boat's speed in still water is 12 km/hour.</span>
4 0
4 years ago
Round 62,322,118,987 . Write the result as the product of a single digit and a power of 10.
Firlakuza [10]

Answer:

6.2 x 10^10

Step-by-step explanation:

5 0
3 years ago
Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.
julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

f(x,y)=4x^2+6y^2

Let g(x,y)=x^2+y^2=1

We have to find the extreme values  of the given function

\nabla f(x,y)

\nabla g(x,y)=

Using Lagrange multipliers

\nabla f(x,y)=\lambda \nabla g(x,y)

f_x=\lambda g_x

8x=\lambda 2x

Possible value x=0 or \lambda=4

If x=0 then substitute the value in g(x,y)

Then, we get y=\pm 1

f_y=\lambda g_y

12y=\lambda 2y

If \lambda=4 and substitute in the equation

Then , we  get possible value of y=0

When y=0 substitute in g(x,y) then we get

x=\pm 1

Hence, function has possible  extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

f(0,1)=6

f(0,-1)=6

f(1,0)=4

f(-1,0)=4

Therefore, the maximum value of f  on the circlex^2+y^2=1  is f(0,\pm1)=6 and minimum value of f(\pm1,0)=4

7 0
3 years ago
Will some one help me please will friend
aliina [53]
Add the equations,just the way they appear there.

-- Add the top 'x' to the bottom 'x'.  Write the sum under the 'x's.
-- Add the '+y' and the '-y'.  Write the sum under the 'y's.
-- Add the '2' and the '4'. Write the sum under them, with n " = " sign
before it.

You should now have an equation with only 'x' in it and no 'y'.
You can easily solve that one and find out the value of 'x'.

Once you know the value of 'x', go back to either one of the original
equations, and plug the number-value of 'x' in place of 'x'.

You'll then have an equation with only 'y' in it and no 'x'.
You can easily solve that one and find out the value of 'y'. 


7 0
4 years ago
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