Answer: d) $369.31 to $380.69
Step-by-step explanation:
Given;
Mean price x= $375
Standard deviation r= $20
Number of retail stores n = 50
Confidence interval of 95%
Z*(95%) = 1.96
Confidence interval = x+/-Z*(r/√n)
= $375+/- 1.96(20/√50)
= $375+/- 5.69
Confidence interval = ($369.31 to $380.79)
a)
well, she put 4000, and she earned in interest 960, so her accumulated amount is just their sum, 4960.
b)
now, it doesn't say, so we're assuming is <u>simple interest</u>, as opposed to compound interest.

c)
let's make the rate 1% greater then, and check
![\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to \stackrel{8+1}{9\%}\to \frac{9}{100}\dotfill&0.09\\ t=years\dotfill &3 \end{cases} \\\\\\ I=(4000)(0.09)(3)\implies I=1080 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{at 9\%}}{1080}-\stackrel{\textit{at 8\%}}{960}\implies \stackrel{\textit{that much more}}{120}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%7D%20%5C%5C%5C%5C%20I%20%3D%20Prt%5Cqquad%20%5Cbegin%7Bcases%7D%20I%3D%5Ctextit%7Binterest%20earned%7D%5Cdotfill%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%244000%5C%5C%20r%3Drate%5Cto%20%5Cstackrel%7B8%2B1%7D%7B9%5C%25%7D%5Cto%20%5Cfrac%7B9%7D%7B100%7D%5Cdotfill%260.09%5C%5C%20t%3Dyears%5Cdotfill%20%263%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20I%3D%284000%29%280.09%29%283%29%5Cimplies%20I%3D1080%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bat%209%5C%25%7D%7D%7B1080%7D-%5Cstackrel%7B%5Ctextit%7Bat%208%5C%25%7D%7D%7B960%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bthat%20much%20more%7D%7D%7B120%7D)
Answer:
Part A) Option A. QR= 3 cm
Part B) Option B. SV=6.5 cm
Step-by-step explanation:
step 1
<u>Find the length of segment QR</u>
we know that
If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
so
In this problem Triangle QRW and Triangle QSV are similar by AA Similarity Theorem
so

we have
---> because S is the midpoint QT (QS=TS)
--->because V is the midpoint QU (QW+WV=VU)
--->because V is the midpoint QU (QV=VU)
substitute the given values

solve for QR

step 2
Find the length side SV
we know that
The <u><em>Mid-segment Theorem</em></u> states that the mid-segment connecting the midpoints of two sides of a triangle is parallel to the third side of the triangle, and the length of this mid-segment is half the length of the third side
so
In this problem
S is the mid-point side QT and V is the mid-point side QU
therefore
SV is parallel to TU
and

so

Answer:
lol
Step-by-step explanation:
This is nice and simple. When ever you get a percentage, there will always be a decimal in front of the 2 farthest numbers. So, 250% could be turn to 2.50 when it comes to calculating another number. So, if you wants to find 250% of 2, you would multiply 2 by 2.5. So, the answer would be
2 x 2.5 = 5
(Another example is if you want to find 50% of 2. You would multiple 2 by .5, which would be 1)