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Taya2010 [7]
3 years ago
6

Which of the following is a cost homeowners insurance does not protect

Mathematics
2 answers:
const2013 [10]3 years ago
6 0

Answer:

c

Step-by-step explanation:

cause the other guy said it

larisa86 [58]3 years ago
5 0
-C... I just saw it on Quizlet
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Is k=6 a solution to the equation: 1/3k = 3
Step2247 [10]

Answer: No it's not

Step-by-step explanation:

1/3 x 6/1 = 6/3

6/3 = 2

8 0
2 years ago
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(1/4)x+1=32 <br><br> -A: -7/2<br> -B: 2<br> -C: -2<br> -D: 3/2
777dan777 [17]
The answer is b due to pemdas
4 0
2 years ago
The function m(w) = –25w + 2500 models the amount of money in a safe, in dollars, w weeks after Lori learned the combination to
elena55 [62]

Answer:

B) There will be no money in the safe 100 weeks after Lori learned the combination.

I hope this answer is right.

5 0
3 years ago
20 points and brainliest <br> I’m in quiz in need it asap <br> Number 4
iren [92.7K]

Answer and step-by-step explanation:

The polar form of a complex number a+ib is the number re^{i\theta} where r = \sqrt{a^2+b^2} is called the modulus and \theta = tan^-^1 (\frac ba) is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4

now we can write the two numbers as

z_1=4e^{-i\frac \pi6}; z_2=e^{i\frac\pi4}

(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4

Now, in the last step I've used the fact that e^{i(2k\pi+x)} = e^i^x ; k\in \mathbb Z, or in other words, the complex exponential is periodic with 2\pi as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.

7 0
2 years ago
How many ways can 6 people be chosen and arranged in a straight line if there are 8 people to choose from? 720 20,160 40,320 48?
Rudik [331]
The number of permutations of 8 people taken 6 at a time is given by:
8P6=\frac{8!}{(8-6)!}=20,160&#10;
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3 years ago
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