Answer:
a=50 b=20
Step-by-step explanation:
Call A and B the 2 present ages.
Ten years from now, A is twice as old as B -->
(A + 10) = 2(B + 10) (1)
Five years ago, A was 3 times as old as B -->
(A - 5) = 3(B - 5) (2).
Solve the system (1) and (2).
From (2) --> A = 3B - 15 + 5 = 3B - 10.
Replace this value of A into (1) -->
3B - 10 + 10 = 2B + 20 --> B = 20. Then,
A = 3B - 10 = 60 - 10 = 50.
Check
!0 years from now --> A = 60 and B = 30 --> A = 2B .OK
5 years ago --> A = 45 and B = 15 --> A = 3B. OK
 
        
             
        
        
        
Answer:
p > 5 and p <-8
Step-by-step explanation:
To solve this, you first need to isolate p. 
First add 6 on both sides of the equation:

Then subtract 3 from both sides of the equation.

The divide both sides by 2.

Another solution is possible because of the absolute value. 
If 
Then 
<em>Thus we can solve the second solution:</em>


Isolate P again by subtracting both sides by 3


Then divide both sides by 2:


 
        
                    
             
        
        
        
Answer:
The answer is 9(7x – 1).
Step-by-step explanation:
63x – 9
3 × 3 × 7 × x – 3 × 3
9(7x – 1)
Thus, The answer is 9(7x – 1).
 
<u>-TheUnknownScientist</u><u> 72</u>
 
        
             
        
        
        
Answer:
Hence the adjusted R-squared value for this model is 0.7205.
Step-by-step explanation:
Given n= sample size=20  
Total Sum of square (SST) =1000  
Model sum of square(SSR) =750  
Residual Sum of Square (SSE)=250  
The value of R ^2 for this model is,  
R^2 = \frac{SSR}{SST}  
R^2 = 750/1000 =0.75  
 Adjusted  :
 :
 
Where k= number of regressors in the model.
