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2 years ago

____ 2. The set of numbers {9, 8, 7, …}

Mathematics

1 answer:

OverLord2011 [107]2 years ago

6 0

Answer:

A. x > -4

Step-by-step explanation:

< less than

>greater than

the unknown number x is greater than -4

{9, 8, 7, ...} the number is counting down. So the next number is 6.

is 6 greater than -4

or less than -4

therefore

x(which is 6) is greater than -4

x > -4

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Profit, P(x), is the difference between revenue, R(x), and cost, C(x), so P(x) = R(x) - C(x). Which expression represents P(x),

harkovskaia [24]

Answer:

x^4-3x^3+x^2-4

Step-by-step explanation:

Given the following functions

R(x) = 2x^4 – 3x^3 + 2x – 1 and

C(x) = x^4 – x^2 + 2x + 3

We are to find the profit function P(x)

P(x) = R(x) - C(x)

P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)

P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3

Collect the like terms

P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3

P(x) = x^4-3x^3+x^2+0-4

P(x) = x^4-3x^3+x^2-4

Hence the required profit function P(x) is x^4-3x^3+x^2-4

5 0

2 years ago

Read 2 more answers

(x-9)(x+2) <br> see if u can find it

ycow [4]

Answer:

x^2 -7x-18

Step-by-step explanation:

(x-9)(x+2)

FOIL

first x*x = x^2

outer 2x

inner -9x

last -9*2 =-18

Add together

x^2 +2x-9x-18

Combine like terms

x^2 -7x-18

4 0

2 years ago

What is the value of log(x exponent 2 y exponent 3 divided by z) when given the following:

Gekata [30.6K]

Answer:

B. 13

Explanation:

$\sf\:Given\:expression: log(\dfrac{x^2 y^3}{z} )$

Logarithm rules:

$\sf (i) \ \sf log(ab) = log(a) + log(b)\\ \\ (ii) \ log(a/b) = log(a) - log(b)\\\\ (iii) \ log(a^n) = n log(a)$

Breakdown of the expression:

$\rightarrow \sf log\left(\dfrac{x^2y^3}{z}\right)$

$\rightarrow \sf log\left(x^2\right) + log\left(y^3\right) - log(z)$

$\rightarrow \sf 2\log\left(x\right)+3\log \left(y\right)-\log \left(z\right)$

insert given values

$\rightarrow \sf 2(3)+3(2)-(-1)$

$\rightarrow \sf 13$

7 0

1 year ago

What is the missing numerator?

Vsevolod [243]

Answer:

The answer is 3

Step-by-step explanation:

........

7 0

1 year ago

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Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

Read 2 more answers