1. y₁ = 70x
2. y₂ = 55x
Solve y₁ - y₂ for x = 11.
(15h^2+10h+25)/(5h)
(15h^2+10h+25)/(5)
(3h^2+2h+5)/(h)
(15h^2+10h+25)/(5h)
(5h)(3h)=15h^2
(10h+25)/(5h)
(5h)(2)=10h
(25)/(5h)=5/h=\=
(15h^2+10h+25)/(5h)= 3h+2, with a remainder of 25
Answer:
x = 136°
Step-by-step explanation:
We can use a theorem to help us.
<em>Theorem: </em>
<em>The measure of an exterior angle of a triangle is equal to the sum of the measures of the remote interior angles.</em>
For exterior angle x, the remote interior angles are z and <CBD.
From the theorem, we get this equation.
x = z + m<CBD
We know z = 52°.
We need to find m<CBD.
Angles CBD and y are a linear pair. They are supplementary, so the sum of their measures is 180°. We are given y = 96°.
m<CBD + y = 180°
m<CBD + 96° = 180°
m<CBD = 84°
x = z + m<CBD
x = 52° + 84°
x = 136°
Answer:
25+144 = 169
Step-by-step explanation:
