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snow_tiger [21]
2 years ago
11

Según la gráfica cuadrática de la expresión y= x² + 1 ¿Cuales serían las coordenadas cuando x es igual a -2,-1 y 0?

Mathematics
1 answer:
Temka [501]2 years ago
5 0

Answer:

When  x =  -2     P  ( -2 ;  5)

When   x = -1       Q  (  -1 ; 2)

When   x  = 0       R  ( 0 ;  1)

Step-by-step explanation:

y =  x²  +  1

When    x  =  -2

y  =  ( -2)²  + 1        y  =  5     point  P  ( -2 ;  5)

When  x  =  -  1

y  =  (  -1)² + 1         y  =  2     point  Q  ( -1 ; 2 )

When x   =  0

y  =  (0)²  +  1         y  =  1      point   R  (  0 ;  1 )

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2 years ago
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Answer the following questions. Make sure to show all your work.
KengaRu [80]

a) Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of  equations

b) since  the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of  equation

In order to show if the given point corresponds to the given function, we will have to substitute the value of x into the function to see if we will have its corresponding y-value

For the point (-0.8, -0.6), substitute x = -0.8 into both functions as shown:

f(x)  = 2x + 1

f(-0.8) = 2(-0.8) + 1

f(-0.8) = -1.6  + 1

f(-0.8) = -0.6

Simiarly;

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y = 2.4 - 3

y = -0.6

Since the corresponding y-value is -0.6, hence the point (-0.8, -0.6) is a solution to the system of  equations

For the point (1/3, 2), substitute x = 1/3 into both functions as shown:

x = (y+2)/2

x = (2+2)/2

x = 4/2

x = 2

Simiarly;

x + 2 = 3

x = 3-2

x = 1

Since the corresponding x-value is not 1/3, hence the point (1/3, 2) is not a solution to the system of  equations

Learn more on systems of equation here: brainly.com/question/847634

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