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vodka [1.7K]
3 years ago
6

The diameter of a sphere is 6 ft 6 in. Find the radius.

Mathematics
1 answer:
Jlenok [28]3 years ago
3 0

Answer:

3 ft 3 in

Step-by-step explanation:

The radius is half the diameter.  

If the diameter is 6 ft 6 in, then the radius is 3 ft 3 in.

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Simultaneous equation <br> Find x and y <br> 2x+y=5<br> X+3y=5
snow_tiger [21]
x+3y=5 \ =>\boxed{x=5-3y} \\\\ 2x+y=5 \\\\ 2(5-3y)+y=5 \\\\10-6y+y=5 \\\\ -5y=5-10 \\\\ -5y=-5 \ |:(-5) \\\\ \boxed{y=1} \\\\ x=5-3*1 \\\\ x=5-3 \\\\ \boxed{x=2}
6 0
3 years ago
Read 2 more answers
Sarkis wants to draw a triangle with sides measuring 4 ft, 10 ft, and 16 ft. Which is true about Sarkis’s plan?
Liono4ka [1.6K]

Answer:

Sarkis cannot draw a triangle with these side lengths.

Step-by-step explanation:

Sarkis cannot draw a triangle with these side lengths.

5 0
2 years ago
Coty painted a right triangle on paper. The hypotenuse of his triangle is 18 inches and one of the legs is 7 inches. What is the
padilas [110]

Answer:

G) 16.6

Step-by-step explanation:

We can use the pythagoriam theroem to solve the problem

a^{2} + b^{2} = c^{2}

a^{2} + 7^{2} = 18^{2}

a^{2} + 49 = 324

a^{2} = 275

a = 16.6

3 0
2 years ago
Given that (x+2) is a factor of x^3+8, find the other quadratic factor.
Semmy [17]
If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4
3 0
2 years ago
The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12
Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

P(x)=-12x^2+120x

To find:

The current that will produce the maximum power.

Solution:

We have,

P(x)=-12x^2+120x

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

In the given function, a=-12 and b=120. So,

-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}

-\dfrac{b}{2a}=-\dfrac{120}{-24}

-\dfrac{b}{2a}=5

Putting x=5 in the given function, we get

P(5)=-12(5)^2+120(5)

P(5)=-12(25)+600

P(5)=-300+600

P(5)=300

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0
3 years ago
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