What is the net force on an object that has a 25N force pulling it to the right, and two 10N forces pulling it to the left?
2 answers:
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Take the derivative with respect to t
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
divide by w
we add sin(wt) to both sides
divide both sides by cos(wt)
OR
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be
since 2npi is just the period of cos
substituting our second soultion we get
since 2npi is the period
so the maximum value =
minimum value =
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
divide by w
we add sin(wt) to both sides
divide both sides by cos(wt)
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be
since 2npi is just the period of cos
substituting our second soultion we get
since 2npi is the period
so the maximum value =
minimum value =
Answer:
74.4°
Step-by-step explanation:
Given
- ∠G=90° => ΔEFG is a right triangle
- EF = 95 feet
- FG = 26 feet
Use sine law to find ∠F
As we know:
Sin(GEF)/ GF = Sin(EGF)/EF
<=> Sin(GEF) / 26 = Sin(90)/95
<=>Sin(GEF) / 26 = 1/95
<=> Sin(GEF) = 26/95
<=> ∠GEF ≈ 15.8°
=> ∠F = 180° - ∠G - ∠GEF
∠F = 180° - 90° - 15.8° = 74.4°
