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maxonik [38]
3 years ago
9

Given \qquad \overline{PQ}\perp\overline{PS} PQ ​ ⊥ PS start overline, P, Q, end overline, \perp, start overline, P, S, end over

line \qquad m \angle QPR = 7x - 9^\circm∠QPR=7x−9 ∘ m, angle, Q, P, R, equals, 7, x, minus, 9, degrees \qquad m \angle RPS = 4x + 22^\circm∠RPS=4x+22 ∘ m, angle, R, P, S, equals, 4, x, plus, 22, degrees Find m\angle QPRm∠QPRm, angle, Q, P, R:
Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer: 40 degrees

Step-by-step explanation:

did this on khan! :)

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Jim washes 2/3 of his car with 1/2 a bottle of soap. What fraction of the soap will he use to clean his entire car?​
Sunny_sXe [5.5K]

Answer:

if he uses 1/2 for 2/3, then you can divide 2/3 and 1.2 by 2 to get the remaining soap needed to complete the wash

so to clean the last 1/3 of the car, he`ll use 1/4 of the remaining soap

the entire car needs <u><em>3/4 of a bottle of soap</em></u>

3 0
3 years ago
Please help me <br> 3(x + 2) * 10 * 7 divided by 70 - 2 (x+2)<br><br> Simplify
I am Lyosha [343]

Answer:

= 105(x+2)/33-x

Step-by-step explanation:

Given the expression

[3(x+2)*10*7]÷70 - 2(x+2)

= 3(x+2)*70÷70 - 2(x+2)

= 210(x+2)/70-2x-4

= 210(x+2)/66-2x

= 210(x+2)/2(33-x)

= 105(x+2)/33-x

8 0
3 years ago
What are the solutions of x^2-2x+37=0?
blsea [12.9K]

Answer:

Answer is x=1+6i x=1-6i

Step-by-step explanation:

3 0
3 years ago
The yearbook club had a meeting. the meeting had 18 people, which is one half of the club. how many people are in the club
Dmitry_Shevchenko [17]

Answer:

36 people

Step-by-step explanation:

If the yearbook club had 1/2 the participants attend the meeting, than all of them would be represented by 18 x 2, or 36 (since two halves make a whole)

8 0
2 years ago
Find the volume of the parallelepiped with adjacent edges t = 3j – 4j – 6k, u = 3i – 7j – 7k and v = 5i + j + 3k.
Assoli18 [71]

Answer:

94 cubic units

Step-by-step explanation:

The volume of this parallelepiped (the product of area of its base and height) is equal to the absolute value of the scalar triple product |\vec{t}\cdot (\vec{u}\times \vec{v})|

Since

\vec{t}=3\vec{i}-4\vec{j}-6\vec{k}=(3,-4,-6)\\ \\\vec{u}=3\vec{i}-7\vec{j}-7\vec{k}=(3,-7,-7)\\ \\\vec{v}=5\vec{i}+\vec{j}+3\vec{k}=(5,1,3)

we have

|\vec{t}\cdot (\vec{u}\times \vec{v})|=\left|\left|\begin{array}{ccc}3&-4&-6\\3&-7&-7\\5&1&3\end{array}\right|\right|=|3\cdot (-7)\cdot 3+(-4)\cdot (-7)\cdot 5+3\cdot 1\cdot (-6)-5\cdot (-7)\cdot (-6)-3\cdot (-7)\cdot 1-3\cdot (-4)\cdot 3|=|-63+140-18-210+21+36|=|-94|=94\ un^3.

4 0
3 years ago
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