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maxonik [38]
3 years ago
9

Given \qquad \overline{PQ}\perp\overline{PS} PQ ​ ⊥ PS start overline, P, Q, end overline, \perp, start overline, P, S, end over

line \qquad m \angle QPR = 7x - 9^\circm∠QPR=7x−9 ∘ m, angle, Q, P, R, equals, 7, x, minus, 9, degrees \qquad m \angle RPS = 4x + 22^\circm∠RPS=4x+22 ∘ m, angle, R, P, S, equals, 4, x, plus, 22, degrees Find m\angle QPRm∠QPRm, angle, Q, P, R:
Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer: 40 degrees

Step-by-step explanation:

did this on khan! :)

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Let b be a number such that (2b+5)(b-1)=6b. What is the largest possible value of b? Express your answer as a common fraction.
Oksi-84 [34.3K]

Answer:

Foil the expression and solve the derivative with respect to b at f'(x)=02b^2+3b+5=6b\\d/dx(2b^2+9b+5=0)\\4b+9=0\\b=-9/4

Step-by-step explanation:

4 0
3 years ago
What is the measure, in degrees, of an angle that represents 50/350 of a circle?
JulsSmile [24]

Answer:

\mathrm{A.\: 50^{\circ} }

Step-by-step explanation:

Since there are 360 degrees in a circle, we can set up the following proportion:

\frac{50}{360}=\frac{x}{360},\\360x=50\cdot 360,\\x=\boxed{50}

8 0
3 years ago
C is the midpoint of AD. B is the midpoint of AC. BC = 12. What is the length of AD
kvasek [131]
48 I would believe is the answer
6 0
3 years ago
Read 2 more answers
HELP PLEASEEE with steps
zysi [14]
<h3>Answer: Choice C) 421.9</h3>

=======================================

Explanation:

You're on the right track. You wrote down the proper expression to get the final answer, assuming you meant to write 75/4 as the third term inside the parenthesis. This works because each time you cut the side length in half to get each smaller triangle's side. The 3 is because there are 3 sides for each of the triangles. Much of this I have a feeling you already know as you wrote down the expression on the page, though I'm not 100% sure of your mindset. Computing this expression leads to 421.875 which rounds to 421.9

note: an alternative is to write 3*75 + 3*75/2 + 3*75/4 + 3*75/8, though that is more work. It's better to have that 3 factored out.

8 0
3 years ago
Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5
zaharov [31]

Answer:

31

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}} or \displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}

Therefore, the solution is 31.

__________________________________________________________

Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as \displaystyle \large{a_{n-1} \cdot r = a_n} meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as:

\displaystyle \large{r=\frac{a_{n+1}}{a_n}}

Once knowing which sequence or series is it, apply an appropriate formula for the series. For geometric series, apply the following three formulas:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}\\\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

Above should be applied for series that have common ratio not equal to 1.

\displaystyle \large{S_n=a_1 \cdot n}

Above should be applied for series that have common ratio exactly equal to 1.

__________________________________________________________

Topics

Sequence & Series — Geometric Series

__________________________________________________________

Others

Let me know if you have any doubts about my answer, explanation or this question through comment!

__________________________________________________________

7 0
3 years ago
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