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Inga [223]
2 years ago
5

7j+5-8k when j =0.5 and k =0.25

Mathematics
1 answer:
Zinaida [17]2 years ago
7 0
Evaluate is just a fancy term for solve.
So to start you’ll want to substitute in the values that you are given and the just solve the sum.
I really hope this was helpful.
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PLS HELP ASAP
Contact [7]

Answers:

Equation is (x+1)^2 + (y+2)^2 = 25

Center is (-1, -2)

Radius = 5

===========================================

Work Shown:

x^2+2x+y^2+4y=20\\\\(x^2+2x)+(y^2+4y)=20\\\\(x^2+2x+1)+(y^2+4y)=20+1\\\\(x^2+2x+1)+(y^2+4y+4)=20+1+4\\\\(x+1)^2 + (y+2)^2 = 25\\\\

center = (h,k) = (-1,-2)

radius = 5

-----------------------------

Explanation:

I grouped up the x and y terms separately. Then I added 1 to both sides to complete the square for the x terms. I cut the 2 from 2x in half, then squared it to get 1. In the next step, I cut the 4 from 4y in half to get 2, which squares to 4. So that's why I added 4 to both sides to complete the square for the y terms.

Each piece is factored using the perfect squares factoring rule which is a^2+2ab+b^2 = (a+b)^2

The last equation is in the form (x-h)^2 + (y-k)^2 = r^2

We can think of x+1 as x - (-1) to show that h = -1

Similarly, y+2 = y-(-2) = y-k to show that k = -2

The center is (h,k) = (-1,-2)

The radius is r = 5 because r^2 = 5^2 = 25 is on the right hand side in the last equation above.

3 0
2 years ago
What does the term "cube root" mean?
Masteriza [31]
Answer:
It means the factor that we multiply by itself three times to get that number.
3 0
3 years ago
Read 2 more answers
Use calculus to find the area of the triangle with the vertices (0, 5), (2, -2), and (5, 1).
guajiro [1.7K]

The area of the triangle with the vertices (0, 5), (2, -2), and (5, 1) by using the calculus is  21 square unit.

We need to find the equation among all possible pairs and then integrate the equations from one co-ordinate to another co-ordinate

Equation of line passing through (0,5) and (2,-2) is

y-5 = [(-2-5)/(2-0)](x-0)

=>y-5 = (-7) /2x

=>y= (-7/2x)+5 -------(eq1)

Equation of line passing through (0,5) and (5,1) is

y-5 = [(1-5) / (5-0)](x-0)

=>y-5 = (-4/5)x

=>y = (-4/5)x+5-------(eq2)

Equation of line passing from (2,-2) and (5,1) is

y-(-2) = [[1 - (-2)] / (5-2)] / (x-2)

=>y+2=(3/3)(x-2)

=>y=x-4--------(eq3)

Now, we use definite integration to find the area between the different equation of line.

So, area enclosed between the equations is given by the

area =\int\limits^5_2[(-4/5)x+5 - (-7/2)x + 5)dx  + \int\limits^5_1[(-4/5)x+5 -(x-4)]dx

=>area=\int\limits^5_2(7/2-4/5)x dx + \int\limits^5_1((-9/5)x+9)dx

Using properties of integration,\int\limits x\, dx=x^{2}/2

=>area=\int\limits^5_2(27/10)x dx + \int\limits^5_1(-9/5)x+9)dx

=>area=([27/10)×[5² - 2²])/2 + [ (-9/5)×(5²-1²) ]/2 +9×(5-1)

=>area=(27/20)×(25-4) + (-9/5)×24+9×4

=>area = (27×21)/20 + (-216)/5+ 36

=>area=(567/20) - (216/5) + 36

=>area= [(567-261×4)+(36×20)]/20

=>area=[(567-864)+720]/20

=>area=423/20

=>area=21 square unit.

Hence, area of triangle is 21 square unit.

To know more about area of triangle, visit here:

brainly.com/question/19305981

#SPJ4

4 0
1 year ago
Which situation could be represented by an exponential function select each correct answer
ANTONII [103]

Answer:

The first and third options are the examples of exponential functions.

Step-by-step explanation:

When a quantity is compounded after a certain interval of time at a certain rate, then we can assume that the situation can be represented by an exponential function.

In the first option:  An event organizer finds each year's attendance for the past five years is about \frac{4}{5} of previous year's attendance.

So, here the total attendance is compounding every year by a factor \frac{4}{5} of previous year's attendance.

Again, in the third case: The total population is increasing by about 7.5% each year.

Hence, the population is compounded every year by 7.5% of the previous year's population.

Therefore, the first and third options are examples of exponential functions. (Answer)

3 0
2 years ago
Solve the following system of linear equations algebraically.<br> 3x + y = 5<br> 5x – 4y = -3
Korvikt [17]

3x+y=5 & 5x-4y=-3

3x+5x=8x+y-4y=-3

           8x+y-4y=-3

     8x+3y=-3

         -3     -3

8x=-6

3 0
2 years ago
Read 2 more answers
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