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3 years ago

7j+5-8k when j =0.5 and k =0.25

Mathematics

1 answer:

Zinaida [17]3 years ago

7 0

Evaluate is just a fancy term for solve.
So to start you’ll want to substitute in the values that you are given and the just solve the sum.
I really hope this was helpful.

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Red toys, green toys, and then blue toys

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4 years ago

Find the slope of the line.<br> a. -1<br> b. 2<br> C. -2<br> d. 1

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I need the graph

Step-by-step explanation:

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3 years ago

Given the equations 9x+3/4y=6 and 2x+1/2y=9, by what factor the equation to eliminate y and solve the system through linea would

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C -3/2

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3 years ago

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Michael has 567 pennies, Jorge has 464 pennies, and Jamie has 661 pennies. If the pennies are shared equally by the 3 boys and 3

GuDViN [60]

Answer:

Everybody, including the three boys, will get 47 pennies.

Step-by-step explanation:

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4 years ago

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

Umnica [9.8K]

The statements and their individual answers are not provided in the question. However, please check the explanation given below for the equation.

Step-by-step explanation:

The equation given is $\frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 }$

Divide the leading term of the dividend by the leading term of the divisor: $\frac{2x^{4} }{2x^{2} } = x^{2}$

Multiply it by the divisor: $x^{2} ({2x^{2} -3x +1) = 2x^{4} - 3x^{3} + x^{2}$

Subtract the dividend from the obtained result: $(2x^{4} + 7x^{3} + 18x^{2} + 11x - 2) - (2x^{4} - 3x^{3} + x^{2} ) = (10x^{3} + 17x^{2} + 11x -2)$

Divide the leading term of the obtained remainder by the leading term of the divisor: $\frac{10x^{3}}{2x^{2} } = 5x$

Multiply it by the divisor: $5x (2x^{2} - 3x + 1) = 10x^{3} - 15x^{2} + 5x$

Subtract the remainder from the obtained result: $(10x^{3} + 17x^{2} + 11x -2) - (10x^{3} - 15x^{2} + 5x) = (32x^{2} + 6x - 2)$

Divide the leading term of the obtained remainder by the leading term of the divisor: $\frac{32x^{2} }{2x^{2} } = 16$

Multiply it by the divisor: $16 (2x^{2} - 3x +1) = 32x^{2} - 48x +16$

Subtract the remainder from the obtained result: $(32x^{2} + 6x - 2) - (32x^{2} - 48x +16) = 54x - 18$

Since the degree of the remainder is less than the degree of the divisor, then we are done.

Therefore, $\frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 } = (x^{2} + 5x +16 + \frac{54x - 18}{2x^{2} - 3x +1})$

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3 years ago

Read 2 more answers