Question

The two bases of a right conical frustum have radii 12 and 9. The two bases are 4 units apart. Let the volume of the frustum be $V$ cubic units and the total surface area of the frustum be $A$ square units. Find $V A$.

Answer 1

$V A$. =21,978 $cm ^3$ cubic units and the total surface area of the frustum

What is frustum?

The area of a right circular cone between the base and a part parallel to the base that does not pass through the vertex is known as the frustum. The distance between the two bases perpendicular to the axis determines the altitude of a frustum on a right circular cone.

The formula for the curved surface area (CSA) of a cone's frustum is pi * l(R + r), where (r) denotes the radius of the smaller circle, (R) denotes the radius of the larger circle, and (l) is the slant height of the frustum.

A frustum of that cone is the region of the solid between the plane and the base where a right circular cone is cut by a plane parallel to its base.

Should be the height, , the slant height, and the radii of the circular bases of a frustum of a cone, then.

L S A frustum = π ( R + r ) l.

The two bases of a right conical frustum have radii 12 and 9. The two bases are 4 units apart. Let the volume of the frustum be $V$ cubic units and the total surface area of the frustum be $A$ square units.

Let r1 =12 cm, $r^2$ =9 cm and h=4 cm

Volume of the dustbin (frustum)=

31 ×π×h×(r 12 +r 22 +r 1 r 2)= 31 × 7

22 × 63 × ($12^2$ + $9^2$ +12 × 9)

=66 (144 + 81 + 108) $cm^3$

=66 × 333 $cm^3$

=21,978 $cm ^3$

Hence, $V A$.  =21,978 $cm ^3$

Learn more about frustum here:

brainly.com/question/14268491

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