V + 160 = 11
v = -149
Hope this helps
Answer:
i love math
Step-by-step explanation:
Answer:
Step-by-step explanation:
First, you should distribute the -1 on the right.
Next, add 8n to both sides. This should cancel out the 8n.
Now, add 8 to both sides. This will get n by itself.
Your answer is n = -2.
Answer:
$18
Step-by-step explanation:
Let's subtract the lunch from the trip total to get the remainding cost!
36.50 - 9.50 = $27
Now let's set up an equation to figure out the amount of the entrance ticket and the gift coupon!
let's have x = the entrance ticket
27 = x + 1/2(x) -----------> 1/2 is next to x, because the gift coupon is 1/2, or 50% of the entrance ticket! Now solve for x!
27 = 3/2x
(2/3) 27 = 3/2x (2/3)
18 = x, so the entrance ticket is $18!
It takes value from a user and then user the operation of (+,-,*/).
i used c++ programming language to solve this program:
#include<iostream>
using namespace std;
int main() {
int var1, var2;
char operation;
cout << "Enter the first number : ";
cin >> var1;
cout << endl;
cout <<"Enter the operation to be perfomed : ";
cin >> operation;
cout << endl;
cout << "Enter the second nuber : ";
cin >> var2;
cout << endl;
bool right_input = false;
if (operation == '+') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 + var2);
right_input = true;
}
if (operation == '-') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);
right_input = true;
}
if (operation == '*') {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 * var2);
right_input = true;
}
if (operation == '/' && var2 != 0) {
cout << var1 << " " << operation << " " << var2 << " = " << (var1 - var2);
right_input = true;
}
if (operation == '/' && var2 == 0) {
cout << "Error. Division by zero.";
right_input = true;
}
if (!right_input) {
cout << var1 << " " << operation << " " << var2 << " = " << "Error;";
cout << "Invalid Operation!";
}
cout << endl;
system("pause");
return 0;
}
