Answer:
Step-by-step explanation:
here you go.
Answer:
![g = 6](https://tex.z-dn.net/?f=g%20%3D%206)
Step-by-step explanation:
1) Diving both sides by 3.
![\frac{18}{3} = g](https://tex.z-dn.net/?f=%20%5Cfrac%7B18%7D%7B3%7D%20%20%3D%20g)
2) Simplify 18/3 to 6.
![6 = g](https://tex.z-dn.net/?f=6%20%3D%20g)
3) Switch sides.
![g = 6](https://tex.z-dn.net/?f=g%20%3D%206)
<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>g</u><u> </u><u>=</u><u> </u><u>6</u>.
a) The points of the other side of the parallelogram are
and
.
b) The points of the other side of the square are
and
.
<h3>
How to find missing points of quadrilaterals</h3>
In this question we shall use vector operations and Pythagorean theorem to determine the location of the missing two points of each quadrilateral.
a) Let be
and
the endpoints of the line segment and
the point of intersection of the diagonals. The remaining points of the parallelogram can be found by the following two formulas:
(1)
(2)
(
,
,
)
![D(x,y) = (-3,5)+2\cdot (2,-1)](https://tex.z-dn.net/?f=D%28x%2Cy%29%20%3D%20%28-3%2C5%29%2B2%5Ccdot%20%282%2C-1%29)
![D(x,y) = (1,3)](https://tex.z-dn.net/?f=D%28x%2Cy%29%20%3D%20%281%2C3%29)
![E(x,y) = (2, 7) + 2\cdot (-3,-3)](https://tex.z-dn.net/?f=E%28x%2Cy%29%20%3D%20%282%2C%207%29%20%2B%202%5Ccdot%20%28-3%2C-3%29)
![E(x,y) = (-4,1)](https://tex.z-dn.net/?f=E%28x%2Cy%29%20%3D%20%28-4%2C1%29)
The points of the other side of the parallelogram are
and
.
b) Let be
and
the endpoints of the line segment, the coordinates of the missing points are found by the following two formulas:
(3)
(4)
Where
is the rotation angle, in degrees.
(
,
,
)
![\overrightarrow{AB} = (2+3, 7-5)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BAB%7D%20%3D%20%282%2B3%2C%207-5%29)
![\overrightarrow{AB} = (5,2)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BAB%7D%20%3D%20%285%2C2%29)
![D(x,y) = (-3, 5) + (5\cdot \cos (-90^{\circ})-2\cdot \sin (-90^{\circ}), 5\cdot \sin (-90^{\circ})+2\cdot \cos (-90^{\circ}))](https://tex.z-dn.net/?f=D%28x%2Cy%29%20%3D%20%28-3%2C%205%29%20%2B%20%285%5Ccdot%20%5Ccos%20%28-90%5E%7B%5Ccirc%7D%29-2%5Ccdot%20%5Csin%20%28-90%5E%7B%5Ccirc%7D%29%2C%205%5Ccdot%20%5Csin%20%28-90%5E%7B%5Ccirc%7D%29%2B2%5Ccdot%20%5Ccos%20%28-90%5E%7B%5Ccirc%7D%29%29)
![D(x,y) = (-1, 0)](https://tex.z-dn.net/?f=D%28x%2Cy%29%20%3D%20%28-1%2C%200%29)
![\overrightarrow{AD} = (-1 + 3, 0-5)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BAD%7D%20%3D%20%28-1%20%2B%203%2C%200-5%29)
![\overrightarrow{AD} = (2, -5)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BAD%7D%20%3D%20%282%2C%20-5%29)
![E(x,y) = (2,7) +(2, -5)](https://tex.z-dn.net/?f=E%28x%2Cy%29%20%3D%20%282%2C7%29%20%2B%282%2C%20-5%29)
![E(x,y) = (4, 2)](https://tex.z-dn.net/?f=E%28x%2Cy%29%20%3D%20%284%2C%202%29)
The points of the other side of the square are
and
. ![\blacksquare](https://tex.z-dn.net/?f=%5Cblacksquare)
To learn more on quadrilaterals, we kindly invite to check this verified question: brainly.com/question/25240753
Answer:
The entire area of the sailboat is 60cm²
Step-by-step explanation:
You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.
In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.
Because the two triangles can be put together to form a single triangle, we don't need to measure them independently. We can simply take the total length of their bases, multiply it by their height, and divide by two. This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.
(2cm + 3cm) × 6cm
= 5cm × 6cm
= 30cm²
The rectangle's area is of course equal to its width times its height, so we can say:
2.5cm × 12cm
= 30cm²
The total area of the shapes then is 30cm² + 30 cm², giving us a total area of 60cm²