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AlexFokin [52]
3 years ago
6

HELP PLEASE 10 POINTS

Mathematics
1 answer:
NeX [460]3 years ago
4 0

Answer:no idea

Step-by-step explanation:

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Explain how using basic facts can help you find 10×20×30×40 mentally?
Katena32 [7]
So all you have to do is take the first numbers of each multiple and multiply them. 
1 x 2 x 3 x 4 = 24 
Now you just add the 4 zeros to your answer. 
240,000 

Our answer even checks! 
10 x 20 x 30 x 40 = 240,000 

Good Luck! :)
3 0
4 years ago
A marijuana survey included 1610 responses from a list of approximately 241,500,000 adults 10) in the U.S. from which every 150.
valentina_108 [34]

Answer:

the Fact that 1610 responses where gotten from the original population of

241 500 000 makes this a convenience sampling.

Step-by-step explanation:

convenience Sampling : this is a type of non-probability sampling that involves the sample being drawn from that part of the population that is close to hand.

8 0
3 years ago
Jim will divide 6 3/4 pounds of candy equally among
yan [13]

Answer:

Halloween question, perfect timing! Your answer would be 2 pounds per friend.

Step-by-step explanation:

Here's how we get this:

First, multiply 3/4 by 6. You'll get 4.5. Let's use a decimal for this equation.

Now, you'll divide 9 by 4.5, to get 2. There's our answer. But we want to double-check and see if it's right.

We can do that by multiplying 4.5 by 2, or 2 by 4.5.

4.5 x 2 = 9

Therefore, your answer is 2 pounds per friend.

Hope I helped! ☺

5 0
3 years ago
Read 2 more answers
Question #12 Please help
julia-pushkina [17]
\bf \textit{logarithm of factors}\\\\
log_a(xy)\implies log_a(x)+log_a(y)
\\\\\\
\textit{Logarithm of rationals}\\\\
log_a\left(  \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\\\
\textit{Logarithm of exponentials}\\\\
log_a\left( x^  b \right)\implies   b\cdot  log_a(x)\\\\
-------------------------------\\\\


\bf a)\\\\
log_9\left( \sqrt[3]{y^2+y} \right)\implies log_9\left[ (y^2+y)^{\frac{1}{3}} \right]\implies \cfrac{1}{3}log_9(y^2+y)
\\\\\\
\cfrac{1}{3}log_9[y(y+1)]\implies \cfrac{1}{3}\left[~log_9(y)~+~log_9(y+1) ~ \right]
\\\\\\
\cfrac{1}{3}log_9(y)~~+~~\cfrac{1}{3}log_9(y+1)


\bf b)\\\\
log_4\left( \frac{a^2b}{\sqrt{c}} \right)\implies log_4(a^2b)~-~log_4(\sqrt{c})\implies log_4(a^2b)~-~log_4(c^{\frac{1}{2}})
\\\\\\\
[~log_4(a^2)~+log_4(b)~]~~-~~\cfrac{1}{2}log_4(c)\\\\\\ log_4(a^2)+log_4(b)-\cfrac{1}{2}log_4(c)
7 0
4 years ago
? - 6= - 7<br> what is the answer
lukranit [14]

Answer:

8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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