Question

Perform the indicated operation. (2a2 - 8)(4a4 + 16a2 + 64)

Answer 1

We have the following expression:

$(2a^2 - 8)(4a^4 + 16a^2 + 64)$

So let's solve this problem step by step.

1st. Applying distributive property:

$(2a^2)(4a^4+16a^2+64)-8(4a^4+16a^2+64)$

2st. Applying distributive property again:

$8a^6+32a^4+128a^2-32a^4-128a^2-512$

3st. Grouping terms with the same base:

$8a^6+(32a^4-32a^4)+(128a^2-128a^2)-512$

4st. Solving, the result is:

$8a^6-512$