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2 years ago

11

Please answer it I really apretiate it

1 answer:

aksik [14]2 years ago

8 0

I'm not sure,..., it might be F.
Can u plz tell me how to get pics on my questions? ?

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Will mark as Brainliest.

Vedmedyk [2.9K]

Here you go good luck

5 0

2 years ago

ASAP NEED HELP THX !! Look at picture

Lana71 [14]

Answer:

66

Step-by-step explanation:

Replace t with 9 in the equation.

$28(1.1)^9$

Simplify.

$28(2.358)$

$66.023$

Rounded, it equals 66

7 0

2 years ago

3/10n = 4/5<br><br> what value of n will make this equation correct?

kirza4 [7]

3/10n = 4/5

n = (4/5)/(3/10)

n = 4/5 * 10/3

n = 8/3

n = 2 2/3

4 0

2 years ago

Solve for n.<br><br> 60 = n/3 + 52

aniked [119]

60= n/3 + 52
-52. -52
8= n/3
You then take 3/1 times 8 therefore you leave n by itself
n = 24

7 0

2 years ago

Read 2 more answers

An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha

BartSMP [9]

Answer:

The decision rule is

Reject the null hypothesis

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 5.6 \ pounds/inch^2$

The sample size is n = 160

The sample mean is $\= x = 5.7 \ pounds/ inch^2$

The variance is $\sigma ^2 = 0.25$

The level of significance is $\alpha = 0.01$

The null hypothesis is $H_o : \mu = 5.6$

The alternative hypothesis is $H_a : \mu > 5.6$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{\sigma ^2 }$

=> $\sigma = \sqrt{0.25 }$

=> $\sigma = 0.5$

Generally the test statistics is mathematically represented as

$z = \frac{\= x - \mu }{ \frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{5.7 - 5.6 }{ \frac{0.5 }{\sqrt{ 160 } } }$

=> $z = 2.53$

From the z table the area under the normal curve to the left corresponding to 2.53 is

$p-value = P(Z > 2.53 ) =0.0057$

From the value obtained we see that the $p-value < \alpha$ hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that the believe that the valve performs above the specifications is true

5 0

2 years ago