Please view my other solution I gave you.
:)
But I will still answer this if you see it.
Because 0.8^x is never 0, then the asymptote is 0-10 or -10.
3x^2 - 4x
Im not quite sure what your asking, so I hope this helps!
<span>The best and easiest way to get it is by using a TI calculator and i hope you can have it, then you can type in the next: invnorm(1 - 0.628) What you are doing is that you are subtracting the probability from 1 because the invnorm function finds the z-score given the probability to the left of the z-score. I think that can help you. </span>
Answer:
reflection
Step-by-step explanation:
Im just learned this so if I'm wrong, i'm sorry >.<
