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dolphi86 [110]
3 years ago
9

Find an equation of the tangent line to the of the function at the given point.

Mathematics
1 answer:
beks73 [17]3 years ago
8 0

Step-by-step explanation:

The slope of the tangent line is equal to the derivative.

f(x) = 3x² − ln x

f'(x) = 6x − 1/x

f'(1) = 6(1) − 1/1

f'(1) = 5

Use point-slope form:

y − 3 = 5 (x − 1)

Simplify:

y − 3 = 5x − 5

0 = 5x − y − 2

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Hey!

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Hope This Helped! Good Luck!

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