Answer:
The probability is 0.9211
Step-by-step explanation:
Let's call K the event that the student know the answer, G the event that the student guess the answer and C the event that the answer is correct.
So, the probability P(K/C) that a student knows the answer to a question, given that she answered it correctly is:
P(K/C)=P(K∩C)/P(C)
Where P(C) = P(K∩C) + P(G∩C)
Then, the probability P(K∩C) that the student know the answer and it is correct is:
P(K∩C) = 0.7
On the other hand, the probability P(G∩C) that the student guess the answer and it is correct is:
P(G∩C) = 0.3*0.2 = 0.06
Because, 0.3 is the probability that the student guess the answer and 0.2 is the probability that the answer is correct given that the student guess the answer.
Therefore, The probability P(C) that the answer is correct is:
P(C) = 0.7 + 0.06 = 0.76
Finally, P(K/C) is:
P(K/C) = 0.7/0.76 = 0.9211
Hi there!
Assuming "Find the product" means multiplying (4x-3) by (3x+8) and factor to it's simplest form the answer would be:
12x²+23x-24
The way you solve this is by using the distributive property of multiplication as shown below:
Start by multiplying -3 from (4x-3) by everything in (3x+8)
3x*(-3) = -9x
8*(-3) = -24
Once you've done that you then multiply everything 4x
4x*8 = 32x
4x*3x = 12x²
(Note: when multiplying two of the same variables like x it means you are multiplying x by itself which is the same as x²)
When you put all of this together it looks like this
12x²+32x-9x-24
from there we combine like terms
32x-9x = 23x
to get
12x²+23x-24
I hope this helps!
God bless,
ASIAX
Answer:
yes
Step-by-step explanation:
Answer:
x = 8
Step-by-step explanation:
Step 1: Simplify both sides.
7 - 3x = -2/5x - 69/5
7 + - 3x = -2/5x + -69/5
-3x + 7 = -2/5x + -69/5
Step 2: Add 2/5x to both sides.
-3x + 7 + 2/5x = -2/5x + -69/5 + 2/5x
-13/5x + 7 = -69/5
Step 3: Subtract 7 from both sides.
-13/5x + 7 - 7 = -69/5 - 7
-13/5x = -104/5
Step 4: Multiply both sides by 5/(-13)
(5/-13) * (-13/5x) = (5/-13) * (-104/5)
x=8
The answer would be it extends to infinity in both directions