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Leviafan [203]
2 years ago
15

Need help asap i have 25minutes left

Mathematics
1 answer:
Yakvenalex [24]2 years ago
3 0

bac=57

Step-by-step explanation:

lmk=50

abc= 63 (if they are parallel)

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Evaluate the expression if a = 2, b = −3, c = −4, h = 6, y = 4, and z = −1.
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(Problem of the Week)
ira [324]

Answer:

He won 13 times and lost 1 time

Step-by-step explanation:

divide 67 by 5 so 67÷5 you would get 13.4 you take the whole number 13 and multiply it by 5 and that will get you to 65 so then you only have 2 left over and if you lose you get 2 point so therefore you know that he lost only once

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3 years ago
Evaluate the limit, if it exists.<br> lim (h - &gt; 0) ((-7 + h)^2 - 49) / h
baherus [9]

Expand everything in the limit:

\displaystyle\lim_{h\to0}\frac{(-7+h)^2-49}h=\lim_{h\to0}\frac{(49-14h+h^2)-49}h=\lim_{h\to0}\frac{h^2-14h}h

We have h approaching 0, and in particular h\neq0, so we can cancel a factor in the numerator and denominator:

\displaystyle\lim_{h\to0}\frac{h^2-14h}h=\lim_{h\to0}(h-14)=\boxed{-14}

Alternatively, if you already know about derivatives, consider the function f(x)=x^2, whose derivative is f'(x)=2x.

Using the limit definition, we have

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h=\lim_{h\to0}\frac{(x+h)^2-x^2}h

which is exactly the original limit with x=-7. The derivative is 2x, so the value of the limit is, again, -14.

4 0
3 years ago
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