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3 years ago

1 Point

Mathematics

2 answers:

natta225 [31]3 years ago

5 0

The answer is 8 maps

natka813 [3]3 years ago

5 0

8 maps is your answer

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Find two whole numbers with a sum of 15 and a product of 54

likoan [24]

A+b=15----(1)
a*b=54----(2)

(1) a=15-b ----(3)

put(3) in(2)

(15-b)*b=54
15b-b^2=54
b^2-15b+54=0
(b-9)(b-6)=0
so b=9 or b=6

if b=9 then a=15-9=6
if b=6 then a=15-6=9

answer two numbers are 6 and 9

3 0

3 years ago

Select the exclusion that fits best with this problem. 13x^6/51x^4

Damm [24]

ANSWER

$x \ne0$

EXPLANATION

The given problem is

$\frac{13 {x}^{6} }{ 51 {x}^{4} }$

This is defined if and only if

$x \ne0$

Even the given expression can be simplified to obtain:

$\frac{13 {x}^{2} }{ 51}$

The exclusion is

$x \ne0$

5 0

3 years ago

1. Find the length of the hypotenuse in triangle ABC. Round your answer to the

tangare [24]

7.6 i could be wrong tho

4 0

2 years ago

PLEASE HELP ASAP!!

Nitella [24]

Answer:

The radius of a sphere is 2 millimeters

The surface area of a sphere is 50.24 square millimeters.

The circumference of the great circle of a sphere is 12.56 millimeters.

Step-by-step explanation:

Verify each statement

case A) The radius of a sphere is 8 millimeters

The statement is false

we know that

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$V=100.48/3\ mm^{3}$

$\pi =3.14$

substitute and solve for r

$100.48/3=\frac{4}{3}(3.14)r^{3}$

$r^{3}=(100.48)/(4*3.14)$

$r=2\ mm$

case B) The radius of a sphere is 2 millimeters

The statement is True

(see the case A)

case C) The circumference of the great circle of a sphere is 9.42 square millimeters

The statement is false

The units of the circumference is millimeters not square millimeters

The circumference is equal to

$C=2\pi r$

we have

$r=2\ mm$

$\pi =3.14$

substitute

$C=2(3.14)(2)$

$C=12.56\ mm$

case D) The surface area of a sphere is 50.24 square millimeters.

The statement is True

Because

The surface area of the sphere is equal to

$SA=4\pi r^{2}$

we have

$r=2\ mm$

$\pi =3.14$

substitute

$SA=4(3.14)(2)^{2}$

$SA=50.24\ mm^{2}$

case E) The circumference of the great circle of a sphere is 12.56 millimeters.

The statement is true

see the case C

case F) The surface area of a sphere is 25.12 square millimeters

The statement is false

because the surface area of the sphere is $SA=50.24\ mm^{2}$

see the case D

7 0

3 years ago

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Apple cost $3.60 for 2lb. at that rate how many pounds of apples can you buy for $5.40

Hoochie [10]

Your answer is 3 lb.

6 0

3 years ago

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