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Helen [10]
3 years ago
13

I’m having a bit of trouble with this

Mathematics
2 answers:
likoan [24]3 years ago
6 0
What is the question?
Leviafan [203]3 years ago
4 0
Hey buddy please specify the trouble so that we can answer that
Thanks
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Factors of 6:factors of 7:
Olenka [21]
6: 1,3,2,6
7: 1,7
Factors of 6 are 1,3,2,6 because 1x6 (6x1) and 3x2. (2x3)

Factors of 7 are 1,7 because seven is a odd number so you can only multiply it by one and itself. (1x7 or 7x1)
6 0
3 years ago
The answer I neeed it now
slava [35]
Anser is B). Subtract smallest number
5 0
3 years ago
Given the two functions, which statement is true?
tia_tia [17]

Answer:

Option D

Step-by-step explanation:

f(x) = \text{log}_{15}x

Transformed form of the function 'f' is 'g'.

g(x) = \frac{1}{2}\text{log}_{15}(x+4)

Property of vertical stretch or compression of a function,

k(x) = x

Transformed function → m(x) = kx

Here, k = scale factor

1). If k > 1, function is vertically stretched.

2). If 0 < k < 1, function is vertically compressed.

From the given functions, k = \frac{1}{2}

Since, k is between 0 and \frac{1}{2}, function f(x) is vertically compressed by a scale factor \frac{1}{2}.

g(x) = f(x + 4) represents a shift of function 'f' by 4 units left.

g(x) = f(x - 4) represents a shift of function 'f' by 4 units right.

g(x) = \frac{1}{2}\text{log}_{15}(x+4)

Therefore, function f(x) has been shifted by 4 units left to form image function g(x).

Option D is the answer.

8 0
3 years ago
Give me the BRAINLIEST ANSWER
oksian1 [2.3K]
Yes there right the answer is three
5 0
3 years ago
A segment in the complex plane has a midpoint at –1 + i. If the segment has an endpoint at –5 – 7i, what is the other endpoint?
morpeh [17]

Answer:

The other end point is: s+ti = 3+9i

Step-by-step explanation:

Mid-Point(M) in the complex plane states that the midpoint of the line segment joining two complex numbers a+bi and s+ti is the  average of the numbers at the endpoints.

It is given by:    M = \frac{a+s}{2} +(\frac{b+t}{2})i

Given: The midpoint = -1 + i and the segment has an endpoint at -5 - 7i

Find the other endpoints.

Let a + bi = -5 -7i  and let other endpoint s + ti (i represents imaginary )

Here, a = -5 and b = -7 to find s and t.

then;

-1+i = \frac{-5+s}{2} + ( \frac{-7+t}{2})i     [Apply Mid-point formula]

On comparing both sides

we get;

-1 = \frac{-5+s}{2}  and  1 = \frac{-7+t}{2}

To solve for s:

-1 = \frac{-5+s}{2}

or

-2 = -5+s

Add 5 to both side we have;

-2+5 = -5+s+5

Simplify:

3 = s or

s =3

Now, to solve for t;

1 = \frac{-7+t}{2}

2 =-7+t

Add 7 to both sides we get;

2+7 = -7+t+7

Simplify:

9 = t

or

t =9

Therefore, the other end point (s+ti) is, 3+9i




4 0
4 years ago
Read 2 more answers
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