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snow_tiger [21]
3 years ago
15

What is an equation of the line that passes through the points (-1, 1) and (-2,-4)?

Mathematics
2 answers:
lina2011 [118]3 years ago
7 0

Answer: The equation is y=5x+6

Step-by-step explanation:

Paha777 [63]3 years ago
6 0

Answer:

y=5x+6

Step-by-step explanation:

(-1,1) and (-2,-4)

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1/2 (x + 8) - 15 = - 3
seropon [69]

Answer:

4

Because I took the test and got it correct.

5 0
2 years ago
Read 2 more answers
PLEASE HELP THANK YOU
arsen [322]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Similarities.

Since here, first figure is a Triangle, hence similarity of a triangle is given by ratio of it sides and make them equate,

hence for,

1.) 16/12 = x/9 ===> 4/3 = x/9 ===> x = 9*4/3 ==> x = 36/3

hence the value of x is 12 , ===> x = 12 .

2.) here,in the case of a Reactangle the relation is such that, length = 2* breadth,

hence we apply the relation,

x = 2*4.5 ===> x = 9 units.

5 0
3 years ago
Given the function f(x)= √x+7, find the value of x when f(x)=1
solniwko [45]
F(x) = 1, so we make the entire equation equal 1.

1 = sqrt(x) + 7

To make x by itself subtract 7 from both sides

-6 = sqrt(x)

Square both sides to remove sqrt from x.

36 = x

The value of x is 36
7 0
3 years ago
*20 POINTS*
Paraphin [41]

Answer:

If you want to use the Rational Zeros Theorem, as instructed, you need to use synthetic division to find zeros until you get a quadratic remainder.

P: ±1, ±2, ±3, ±6  (all prime factors of constant term)

Q: ±1, ±7              (all prime factors of the leading coefficient)

P/Q: ±1, ±2, ±3, ±6, ±1/7, ±2/7, ±3/7, ±6/7  (all possible values of P/Q)

Now, start testing your values of P/Q in your polynomial:

f(x)=7x4-9x3-41x2+13x+6

You can tell f(1) and f(-1) are not zeros since they're not = 0Now try f(2) and f(-2):

f(2)=7(16)-9(8)-41(4)+13(2)+6

       112-72-164+26+6 ≠ 0

f(-2)=7(16)-9(-8)-41(4)+13(-2)+6

       112+72-164-26+6 = 0  OK!! There is a zero at x=-2

This means (x+2) is a factor of the polynomial.

Now, do synthetic division to find the polynomial that results from

(7x4-9x3-41x2+13x+6)÷(x+2):

-2⊥ 7   -9   -41    13     6

         -14   46   -10    -6          

      7  -23   5       3     0     The remainder is 0, as expected

The quotient is a polynomial of degree 3:

7x3-23x2+5x+3

Now, continue testing the P/Q values with this new polynomial.  Try f(3):

f(3)=7(27)-23(9)+5(3)+3

      189-207+15+3 = 0  OK!!  we found another zero at x=3

Now, another synthetic division:

3⊥ 7   -23    5     3

          21   -6   -3_

    7    -2    -1    0  

The quotient is a quadratic polynomial:

7x2-2x-1  This is not factorable, you need to apply the quadratic formula to find the 3rd and 4th zeros:

x= (1±2√2)÷7

The polynomial has 4 zeros at x=-2, 3, (1±2√2)÷7

Step-by-step explanation:

7 0
3 years ago
The relationship between the Fahrenheit (F) and Celsius (C) temperature scales is given by the linear function below.
AlexFokin [52]
relationship \ is \ expressed \ by : \\\\ F =  \frac{9}{5}\cdot  C +
 32 \\ \\ this \ equation \ is \ in \ the \ slope-intercept \ form \ of \
 y = mx + b \ where:\\\\"m"  \ is \ the \ slope \ and \ "b" \ is \ the \
 y-intercept \\\\ slope : \ m=\frac{9}{5} \\ \\y-intercept : \ 
b=32

6 0
3 years ago
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