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AURORKA [14]
3 years ago
13

Random question, BUT is God real?

Mathematics
2 answers:
max2010maxim [7]3 years ago
4 0
<h2>Yes</h2>

<h2>GOD IS REAL SPIRITUALLY BUT NOT PHYSICALLY REAL</h2>

yuradex [85]3 years ago
3 0

Answer:

Yes of course God is real.

Step-by-step explanation:

One way god is  to prove that God is real is to simply look at the world in which we live. The beauty, complexity and organization of the material world around us point toward a master Designer.

You might be interested in
1. Write out the law of cosines and find the hypotenuse of triangle with 2 sides lengths equal to three and the included angle m
LUCKY_DIMON [66]

Answer:

1.) \sqrt{13.341}  ≈ 3.652

2.) I would say something about how the A in front of cos in the equation would change to 90, rather than stay 75 (in the equation for the step by step), but it would be easier to just use the Pythagorean theorem.

Step-by-step explanation:

I think we may have the same class so hopefully this helps:

1.) a^2 = b^2 + c^2 - 2bccosA --> law of cosines formula.

   a^2 = 3^2 + 3^2 - 2(3)(3)cos(75) --> plugged in numbers; when you draw the triangle, the included angle would be A, and the opposite side would be a. B and b, and C and c are opposite each other. In this case, a is the hypotenuse.

   a^2 = 18 - 18cos75 --> in between steps.

   a^2 = 13.341 --> more simplifying.

   a(hypotenuse) = \sqrt{13.341} or 3.652 --> answer

2.) This one is just an explanation: The 75 in the equation is the given angle, which is a. If this changes, it would just change in the equation too. And obviously, if it's 90 degrees, you can just use Pythagorean theorem a^2+b^2=c^2.

Good luck! :)

   

6 0
3 years ago
Gary has twice as many m&amp;ms as larry. Jerry has three times as many m&amp;ms as larry. Together the tree men have 108 m&amp;
Igoryamba

Answer:

36

Step-by-step explanation:

Let number of m&ms Garry has be g

number of m&ms Larry has be l

Number of m&ms Jerry has be j

Since Gary has TWICE as Larry, we can write:

g = 2l

Also, Jerry has THRICE as Larry, we can write:

j = 3l

Together, they have 108, thus, we can write:

g + l + j = 108

Putting 1st and 2nd equation in 3rd, we can solve for Larry first. Shown below:

g + l + j = 108\\2l+l+3l=108\\6l=108\\l=\frac{108}{6}\\l=18

Larry has 18. To find Gary's number, we can use the fact g = 2l, so

g = 2 * 18 = 36

Gary has 36 m&ms

5 0
3 years ago
0&gt;3x-3-6 what is the answer
larisa86 [58]
The answer to this problem is X<3
3 0
3 years ago
Read 2 more answers
Find the area of the rectangle.
Leno4ka [110]
Length multiplied by Width is Area, or A = L x W. 5/9 x 7/8 is your answer.
3 0
3 years ago
Read 2 more answers
Suppose that $4000 is placed in a savings account at an annual rate of 6.4%, compounded quarterly. Assuming that no withdrawals
s2008m [1.1K]

Answer:

3.25 years (nearest hundredth)

Step-by-step explanation:

<u>Compound Interest Formula</u>

\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • A = $4916
  • P = $4000
  • r = 6.4% = 0.064
  • n = 4 (quarterly)

Substitute the given values into the formula and solve for t:

\implies \sf 4916=4000\left(1+\frac{0.064}{4}\right)^{4t}

\implies \sf 4916=4000\left(1.016\right)^{4t}

\implies \sf \dfrac{4916}{4000}=\left(1.016\right)^{4t}

\implies \sf \dfrac{1229}{1000}=\left(1.016\right)^{4t}

\implies \sf \ln \left(\dfrac{1229}{1000}\right)=\ln \left(1.016\right)^{4t}

\implies \sf \ln \left(\dfrac{1229}{1000}\right)=4t \ln \left(1.016\right)

\implies \sf t=\dfrac{\ln \left(\frac{1229}{1000}\right)}{4\ln \left(1.016\right)}

\implies \sf t=3.247594892...

Therefore, it will take 3.25 years (nearest hundredth) for the account to grow to $4916.

Learn more about compound interest here:

brainly.com/question/27747709

brainly.com/question/27806277

8 0
2 years ago
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