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Alja [10]
3 years ago
15

Suppose a city with population 300,000 has been growing at a rate of 5% per year. If this rate continues, find the population of

this city in 12 years
Mathematics
1 answer:
Rzqust [24]3 years ago
5 0

Answer:

538,757

Step-by-step explanation:

Population=(current population)*(1+rate)^(year)

Population=(300000)*(1+5/100)^12=538,756.899 or 538,757. Love from Gauthmath

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450 high school freshmen were randomly selected for a national survey. Among survey participants, the mean grade-point average (
umka21 [38]

Answer:

The margin of error is of 0.01.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.7}{2} = 0.15

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.15 = 0.85, so Z = 1.037.

The margin of error is of:

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation was 0.21.

This means that \sigma = 0.21

Sample of 450:

This means that n = 450

What is the margin of error, assuming a 70% confidence level, to the nearest hundredth?

M = z\frac{\sigma}{\sqrt{n}}

M = 1.037\frac{0.21}{\sqrt{450}}

M = 0.01

The margin of error is of 0.01.

4 0
3 years ago
Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

f'(x)>0

To find its decreasing interval :

f'(x)

2) Then let's find the critical point of this function:

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

8 0
3 years ago
If shape 1 is a scaled copy of shape 2, what angle corresponds to angle C?
GrogVix [38]

Step-by-step explanation:

Angle W is the corresponds as to angle C

6 0
3 years ago
What SPC tool best indicates the shape of the data population and indicates if there are any gaps in the data
romanna [79]
The gaps in the area needs to be closed so the data you use is lenient
7 0
2 years ago
Find the distance between (3,7) and (6,5)
zubka84 [21]

Answer:

square root of five but if it needs to be simplified then 2.24 (rounded)

Step-by-step

8 0
3 years ago
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