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Keith_Richards [23]
3 years ago
12

Brenda wants to hire a lawn service to mow her yard for the summer. G &B lawn service charges a total of 440 for the first 1

0 cutting, plus $40 for each additional cutting. how many cutting can Brenda get for $1000?
Mathematics
1 answer:
vampirchik [111]3 years ago
5 0
Brenda can get 24 cuttings total for $1000
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To make a certain shade of orange calvin uses a rate of 2 ounces of yellow paint to 5 ounces of red paint if he uses 200 ounces
ycow [4]
Answer: 80 ounces of yellow paint

Working:
As we know 2 ounces of yellow paint to 5 ounces of red paint, we can make a ratio:

2:5

Then we look at the question which says 200 ounces of red paint, so we replace the 5 ounces of red paint in the ratio with 200.

2:200

Then we figure out how much the 5 has been multiplied by to get to 200. We do this by doing

200 divide 5 = 40

Therefore we times the 2 ounces of yellow paint by 40 which gets us:

80:200

We can think of it as a fraction too to confirm our answer:

Simplify 80 / 200

We get 2 / 5.

If you need me to further explain something please just ask :)
4 0
2 years ago
What is 0.000025(800)^2 - 0.04(800) +40..?
Scilla [17]

Answer:

24

Step-by-step explanation:

6 0
2 years ago
:) got to love math lol
zzz [600]
Oof im bad at math XD
7 0
3 years ago
Read 2 more answers
Whats is 2400000 in standard form
Ghella [55]
The best answer would be 
2.4 x 10 ^6
10 to the sixth power multiplied by 2.4
7 0
3 years ago
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Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

4 0
2 years ago
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