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2 years ago

Select the correct answer.

Mathematics

1 answer:

GuDViN [60]2 years ago

8 0

The surface area of the pencil is the amount of space it covers

The surface area of the pencil is 61 square centimeters

<h3>How to determine the surface area?</h3>

The given parameters are:

H = 20 cm

L = 0.5 cm

The surface area (SA) is then calculated as:

SA = 6LH + 3 $\sqrt 3$ L^2

This gives

SA = 6 * 0.5 * 20 + 3 $\sqrt 3$ * 0.5^2

Evaluate the sum

SA = 61

Hence, the surface area of the pencil is 61 square centimeters

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the point 3,2 lies on a circle.what is the exact length of the radius of this circle if the center is located at (-1,-4)

Crazy boy [7]

You can use the distance formula to solve this.

Distance Formula:
$d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}$

I am going to use point (3,2) as point 1 and (-1,-4) as point 2
Insert the points into the formula
$d = \sqrt{(X_2 -X_1)^2 + (Y_2 - Y_1)^2}$
$d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}$
Solve:
$d = \sqrt{((-1) - 3)^2 + ((-4) - 2)^2}$
$d = \sqrt{(-4)^2 + (-6)^2}$
$d = \sqrt{16 + 36}$
$d = \sqrt{52}$
$d = \sqrt{52} = \sqrt{4}\sqrt{13}$
$d = \sqrt{52} = 2 \sqrt{13}$
$d = 2 \sqrt{13}$
$radius = 2 \sqrt{13} = 7.2111$

5 0

3 years ago

Jennifer bought 5 meters of ribbon. She gave 2 meters of ribbon to her sister. Jennifer will use some or all of the remaining ri

Sergeu [11.5K]

She has = 5- 2 = 3

3 >= y * 0.55 > 0.55

5 > y > 1 (truncate in case of count)

6 0

3 years ago

A basketball team wants to paint half of a free-throw circle grey. If the circumference of the free-throw circle is 30.77 feet,

Anton [14]

Answer:

37.69 (≈ 38 ft²)

Step-by-step explanation:

2πr = 30.77

r = 30.77 / (2 * 3.14) = 4.9

half of free-throw circle area: πr² / 2 = (3.14 * 4.9²) / 2 = 37.69 (≈ 38 ft²)

3 0

3 years ago

Round 35295 to the nearest thousand

Alex_Xolod [135]

35000, rounding down from five.

4 0

3 years ago

Read 2 more answers

X²+Y²=250 and XY=117<br> What are the values of X and Y?

yan [13]

Answer:

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$

6 0

3 years ago