<u>Answer:</u>
- The fraction '6/3' is an improper fraction
<u>Explanation:</u>
There are 3 types of fractions
- Improper fraction
- Mixed fraction
- Proper fraction
<u>The fraction '6/3' is an improper fraction</u><u> because its numerator is larger than the denominator.</u> If we were looking at 2/3, that fraction would've been classified as a proper fraction because its numerator is smaller than the denominator. <u>An interesting fact is that an improper fraction can be converted to a mixed fraction, even if it is a whole number.</u> 6/3 can be written as 1 3/3, which is 6/3. To convert mixed fraction to improper fraction, simply multiply the denominator and add the numerator.
Hoped this helped.
Answer:
The correct option is (D).
Step-by-step explanation:
To construct the (1 - <em>α</em>)% confidence interval for population proportion the distribution of proportions must be approximated by the normal distribution.
A Normal approximation to binomial can be applied to approximate the distribution of proportion <em>p</em>, if the following conditions are satisfied:
In this case <em>p</em> is defined as the proportions of students who ride a bike to campus.
A sample of <em>n</em> = 125 students are selected. Of these 125 students <em>X</em> = 6 ride a bike to campus.
Compute the sample proportion as follows:
Check whether the conditions of Normal approximation are satisfied:
Since 
, the Normal approximation to Binomial cannot be applied.
Thus, the confidence interval cannot be used to estimate the proportion of all students who ride a bike to campus.
Thus, the correct option is (D).
<span>The answer to the question asked above is as follows:
1 dozen = 12 pieces
3 dozen = (12 pieces)(3) = 36 pieces
thus :
If 3 dozen apples is $4.50 , each piece would be $4.50 / 36 pieces.
So $0.125 per piece of apple.
</span>
Hope my answer would be a great help for you. <span>If you have more questions feel free to ask here at Brainly.
</span>
Let <em>n</em> be the unknown number. We can write it as
<em>n</em> = 10<em>a</em> + <em>b</em>
with <em>a</em> and <em>b</em> integers between 1 and 9 (either with positive or negative sign).
Reversing the digits gives another number
<em>m</em> = 10<em>b</em> + <em>a</em>
The first number is increased by 54 when the digits are reversed, which means
<em>m</em> = <em>n</em> + 54 → 10<em>b</em> + <em>a</em> = 10<em>a</em> + <em>b</em> + 54 → 9<em>b</em> - 9<em>a</em> = 54 → <em>b</em> - <em>a</em> = 6
The digit in the tens place of <em>n</em> is 3 times the digit in the ones place, so
<em>a</em> = 3<em>b</em>
Substitute this into the previous equation and solve for <em>b</em> :
<em>b</em> - <em>a</em> = <em>b</em> - 3<em>b</em> = -2<em>b</em> = 6 → <em>b</em> = -3
Solve for <em>a</em> :
<em>a</em> = 3<em>b</em> = 3(-3) = -9
Then the original number is <em>n</em> = 10<em>a</em> + <em>b</em> = 10(-9) + (-3) = -93
