<span>A) How many cups of flour are there per serving?
</span>1 ½ cups of flour --------<span>6 servings
? cups of flour ------- 1 serving
</span>1 ½
------------
6
= 3/2 x 1/6
= 1/4
answer: 1/4 cups of flour per serving
<span>B) how many total cups of sugar(white and brown) are there per serving?
</span>total white and brown: <span>2/3 + 1/3 = 3/3 = 1 cups (combine)
1 cup of sugar (white and brown) </span>--------6 servings
? cups of sugar (white and brown) ------ 1 serving
1
----- = 1/6
6
answer: 1/6 cups of sugar (white and brown) per serving
<span> (c) Suppose you modify the recipe so that it makes 9 servings. How much more flour do you need for the modified recipe than you need for the original recipe?
</span>
3/2 cups of flour --------6 servings
? cups of flour -----------9 servings
9 * 3/2
-----------
6
= (13 1/2) / 6
= 2 1/4
2 1/4 ( 9 servings) - 1 1/2(6 servings) = 3/4 cups
answer: you need 3/4 more cups of flour
Answer:
2,123.7 square inches
Step-by-step explanation:
C is the correct answer I believe
Answer:
A=6 and B=4.5
Step-by-step explanation:
You are given table
![\begin{array}{cccccc}x&2&4&[A]&7&9\\y&1&2&3&3.5&[B]\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccccc%7Dx%262%264%26%5BA%5D%267%269%5C%5Cy%261%262%263%263.5%26%5BB%5D%5Cend%7Barray%7D)
If the paired values are in a proportional relationship, then
![\dfrac{2}{1}=\dfrac{4}{2}=\dfrac{[A]}{3}=\dfrac{7}{3.5}=\dfrac{9}{[B]}.](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B1%7D%3D%5Cdfrac%7B4%7D%7B2%7D%3D%5Cdfrac%7B%5BA%5D%7D%7B3%7D%3D%5Cdfrac%7B7%7D%7B3.5%7D%3D%5Cdfrac%7B9%7D%7B%5BB%5D%7D.)
Note that
then
![\dfrac{[A]}{3}=2\Rightarrow [A]=6,\\ \\\dfrac{9}{[B]}=2\Rightarrow [B]=\dfrac{9}{2}=4.5.](https://tex.z-dn.net/?f=%5Cdfrac%7B%5BA%5D%7D%7B3%7D%3D2%5CRightarrow%20%5BA%5D%3D6%2C%5C%5C%20%5C%5C%5Cdfrac%7B9%7D%7B%5BB%5D%7D%3D2%5CRightarrow%20%5BB%5D%3D%5Cdfrac%7B9%7D%7B2%7D%3D4.5.)
