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ElenaW [278]
3 years ago
10

Suppose we wish to construct a line segment containing point A and perpendicular to segment BC. To do so with the fewest compass

measurements, we should first A) place the compass point at A. B) place the compass point at B. C) place the straightedge on segment BC. D) place the straightedge on points A and B.
Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
8 0

Place the compass point on point A. I was thinking B, but its not.


Katen [24]3 years ago
5 0
<h3><u>Answer:</u></h3>

The first step in the construction is:

A) place the compass point at A.

<h3><u>Step-by-step explanation:</u></h3>

For the construction of the line segment containing point A and and perpendicular to segment BC using straight edge and compass we have to follow the steps as:

1) Place the point of the compass on the given point and draw a arc on the line on either side of the given point.

2) Then increase the width of the compass and place the point on the compass on the new point where the above arc intersect the line segment.and make arc from both the points.

3) Join the point of intersection of the new arc to the original point A and hence obtain the perpendicular line.

Hence, the first step in the construction is:

A) place the compass point at A.

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3 years ago
Iris weighed 5 large watermelons from her garden. Here are the weights in pounds. 17,11,21,24,22 what is the mean weight
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Answer:

Mean weight = 19 pounds

Step-by-step explanation:

From the question given above, the following data were obtained:

17, 11, 21, 24, 22

Number of data (n) = 5

Mean weight =?

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