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ElenaW [278]
3 years ago
10

Suppose we wish to construct a line segment containing point A and perpendicular to segment BC. To do so with the fewest compass

measurements, we should first A) place the compass point at A. B) place the compass point at B. C) place the straightedge on segment BC. D) place the straightedge on points A and B.
Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
8 0

Place the compass point on point A. I was thinking B, but its not.


Katen [24]3 years ago
5 0
<h3><u>Answer:</u></h3>

The first step in the construction is:

A) place the compass point at A.

<h3><u>Step-by-step explanation:</u></h3>

For the construction of the line segment containing point A and and perpendicular to segment BC using straight edge and compass we have to follow the steps as:

1) Place the point of the compass on the given point and draw a arc on the line on either side of the given point.

2) Then increase the width of the compass and place the point on the compass on the new point where the above arc intersect the line segment.and make arc from both the points.

3) Join the point of intersection of the new arc to the original point A and hence obtain the perpendicular line.

Hence, the first step in the construction is:

A) place the compass point at A.

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Leviafan [203]

Answer:

53%

Step-by-step explanation:

48/90, then multiplied by 100

3 0
3 years ago
I'll give brainliest and points to whomever answers these two questions, thank you so much in advance!
podryga [215]

Answer:

Answer b of the first one

answer of q9

Step-by-step explanation:

(x+iy)(2−3i)=4+i

2x−(3x)i+(2y)i−3yi

2

=4+i

Real

2x+3y

​

​

+

Imaginary

(2y−3x)

​

​

i=4+i

Comparing the real & imaginary parts,

2x+3y=4--------------------------(1)

2y−3x=1----------------------------(2)

Solving eq(1)  &  eq(2),

4x+6y=8

−9x+6y=3

13x=5⇒x=

13

5

​

y=

13

14

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∴(x,y)=(

13

5

​

,

13

14

​

)

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23

SIMILAR QUESTIONS

star-struck

If e

x+iy

=α+iβ, then x+iy is called logarithm of α+iβ to the base e.∴log

e

​

(x+iy)=log

e

​

(re

iθ

) =log

e

​

r+iθ where r is modulus value of x+iy & θ be the argument of x+iy If i

α+iβ)

=α+iβ, then α

2

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2

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Hard

View solution

>

The modulus of (1 + i) (1 + 2i) (1 + 3i) is equal to

3 0
2 years ago
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20 - 5 X 2 + 6 what is order of operation​
serious [3.7K]

Answer:

Parenthesis ()

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3 0
3 years ago
According to national data, 5.1% of burglaries are cleared with arrests. A new detective is assigned to six different burglaries
blagie [28]

Answer:

26.95% probability that at least one of them is cleared with an arrest

Step-by-step explanation:

For each burglary, there are only two possible outcomes. Either it is cleared, or it is not. The probability of a burglary being cleared is independent of other burglaries. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5.1% of burglaries are cleared with arrests.

This means that p = 0.051

A new detective is assigned to six different burglaries.

This means that n = 6

What is the probability that at least one of them is cleared with an arrest?

Either none are cleared, or at least one is. The sum of the probabilities of these events is 100% = 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1)

Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.051)^{0}.(0.949)^{6} = 0.7305

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7305 = 0.2695

26.95% probability that at least one of them is cleared with an arrest

8 0
3 years ago
Jermayne had 30 Apple he give 2/3 pf the apple to kath how many did he have left .
aleksklad [387]
She gave 2/3 so she has 1-2/3=1/3 left.

that makes 30*1/3=30/3=10 apples left
8 0
3 years ago
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