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3 years ago

Solve this inequality for x. 81-1 1/5 x <55

Mathematics

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

A. x > 21 2/3

Step-by-step explanation:

x is greater than 21 and two thirds

i did the math :]

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A regular pyramid has a square base with sides of length 1. The four triangular faces are isosceles triangles whose equal sides

lawyer [7]

Answer:

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Step-by-step explanation:

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5 0

3 years ago

The perimeter of a stop sign has a perimeter of 16x2 - 80x. What is the length of one side?

uranmaximum [27]

Since a stop sign is an octagon it has eight sides. So the perimeter will be:

p=8x, p=perimeter and x=side length. We are told that the perimeter is equal to:

16x^2-80x so we can say:

16x^2-80x=8x subtract 8x from both sides

16x^2-88x=0 factor out 8x

8x(2x-11), since we know x>0

x=11/2

x=5.5 units

7 0

3 years ago

Suppose that only 25% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe

Juliette [100K]

Answer:

$X \sim Binom(n=15, p=0.25)$

For this case we can use the probability mass function and we got:

$P(X= 5) = (15C5) (0.25)^{5} (1-0.25)^{15-5}= 0.165$

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.25)$

For this case we can use the probability mass function and we got:

$P(X= 5) = (15C5) (0.25)^{5} (1-0.25)^{15-5}= 0.165$

5 0

3 years ago

laiz [17]

Answer:

B) 0.02

Step-by-step explanation:

<u>Use the Binomial Theorem</u>

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=4)=\binom{30}{4}(0.30)^4(1-0.30)^{30-4}\\\\P(X=4)=\frac{30!}{4!(30-4)!}(0.30)^4(0.70)^{26}\\ \\P(X=4)=\frac{30!}{4!(26)!}(0.30)^4(0.70)^{26}\\ \\P(X=4)=\frac{30*29*28*27}{4*3*2*1}(0.30)^4(0.70)^{26}\\ \\P(X=4)=27405(0.30)^4(0.70)^{26}\\\\P(X=4)\approx0.0208$

We have the probability of success, $p=0.30$ , and the probability of failure, $q=1-0.30=0.70$ . The binomial coefficient, $\binom{n}{k}$ , represents the amount of possible combinations that $k$ items can be chosen out of $n$ items, with its respective formula $\frac{n!}{k!(n-k)!}$ .

Hence, the best choice for the probability that 4 students chosen at random from the class of 30 that want the next test to be on Monday will be option B, 0.02

7 0

2 years ago

What are the last 2 digits of 7 to the power of 2018. This question was on a past exam paper.

Xelga [282]

Answer:

Step-by-step explanation:

Try finding pattern of last two digits of 7 to the power of some numbers.

7^1=07

7^2=49

7^3=343

7^4= 2301

7^5= 16807

so , the pattern is, 07,49,43,01

so, if we start writing all numbers from 1 to 2018 , four number in each line, 2018 will fall in the second column.

so it will have 49 as the last 2 digits [by seeing this pattern : 07,49,43,01 ]

6 0

3 years ago