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3 years ago

Help me fast please!?!!?!?!

Mathematics

2 answers:

sladkih [1.3K]3 years ago

5 0

The answer for the question is 31

Amiraneli [1.4K]3 years ago

3 0

It would be 31. After each term, you are adding the next even number. Ex. 1 + 2 = 3. 3 + 4 = 7. 7 + 6 = 13. 13 + 8 = 21. 21 + 10 = 31.

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I don't understand number 8

Norma-Jean [14]

Let's try plugging in some negative numbers. Let's do x=-1. 5+-1=4. So we know that if we put in a negative number for x, then n will be positive. But what if we do a number greater than -5, because 5+-5=0. So let's try x=-6. So 5+(-6)=-1. Hmm. So here it is. We know that any number under -5 will be positive and any number above -5 will be negative.

8 0

3 years ago

~PLEASE HELP!~

Gwar [14]

I'm not sure, but what I got was -8.5, since it is only stating that it is -17 and 5, and you need to figure out Point B, when it is between A and 0. So, you don't pay attention to 1-5. You only want -17 through 0. -17 divided by two would be -8.5

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4 years ago

Find the value of x to the nearest tenth

Salsk061 [2.6K]

Answer:

x = 41.2

Step-by-step explanation:

Assuming the dotted line at the top is parallel to the segment with length x, it follows from the alternate interior angles theorem that the interior angle of the triangle (marked in diagram) is also 27º.

Using SOH-CAH-TOA, we get that tan(27º) = 21/x, so x = 21/tan(27º), which is approximately equal to 41.2.

5 0

3 years ago

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What is the completely factored form of d4 -8d2 + 16

irinina [24]

According to Vieta's Formulas, if $x_1,x_2$ are solutions of a given quadratic equation:

$ax^2+bx+c=0$

Then:

$a(x-x_1)(x-x_2)$ is the completely factored form of $ax^2+bx+c$ .

If choose $x=d^2$ , then:

$\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm \sqrt{64-64} }{2}=4$

So, according to Vieta's formula, we can get:

$x^2-8x+16=(x-4)(x-4)= (x-4)^2$

But $x=d^2$ :

$d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2$

8 0

3 years ago

Which number have the same value as 20 tens

fomenos

The answer is 200. 20*10=200

6 0

3 years ago

Read 2 more answers