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ludmilkaskok [199]
2 years ago
8

Find the ratio of triangles to circles in the diagram below

Mathematics
1 answer:
Sedaia [141]2 years ago
7 0

Answer:

Ratio should be equal so ratio is 3:3

<h3 /><h3>PLEASE MARK ME BRAINLIEST.</h3>
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The volume of a right triangular prism is 72 cubic feet. The height of the prism is 9 feet. The triangular base is an isosceles
Alexxx [7]
What is the area of the triangular base?
8 square feet

What is the length of edge DF?
4 feet
3 0
3 years ago
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Use the ratio of a 30-60-90 triangle to solve for the variables. Make sure to simplify radicals. Leave your answers as radicals
Lelu [443]

Answer:

A. v = 19√3.

B. u = 38.

Step-by-step explanation:

The following data were obtained from the question:

Angle θ = 60°

Adjacent = 19

Opposite = v

Hypothenus = u

A. Determination of the value of 'v'

The value of v can be obtained by using Tan ratio as shown below:

Angle θ = 60°

Adjacent = 19

Opposite = v

Tan θ = Opposite /Adjacent

Tan 60 = v/19

Cross multiply

v = 19 × Tan 60

Tan 60 = √3

v = 19 × √3

v = 19√3

Therefore, the value of v is 19√3

B. Determination of the value of 'u'

The value of u can be obtained by using cosine ratio as shown below:

Angle θ = 60°

Adjacent = 19

Hypothenus = u

Cos θ = Adjacent /Hypothenus

Cos 60 = 19/u

Cos 60 = 1/2

1/2 = 19/u

Cross multiply

u = 2 × 19

u = 38

Therefore, the value of u is 38.

6 0
3 years ago
In how many ways can 100 identical chairs be distributed to five different classrooms if the two largest rooms together receive
Eva8 [605]

Answer:

There are 67626 ways of distributing the chairs.

Step-by-step explanation:

This is a combinatorial problem of balls and sticks. In order to represent a way of distributing n identical chairs to k classrooms we can align n balls and k-1 sticks. The first classroom will receive as many chairs as the amount of balls before the first stick. The second one will receive as many chairs as the amount of balls between the first and the second stick, the third classroom will receive the amount between the second and third stick and so on (if 2 sticks are one next to the other, then the respective classroom receives 0 chairs).

The total amount of ways to distribute n chairs to k classrooms as a result, is the total amount of ways to put k-1 sticks and n balls in a line. This can be represented by picking k-1 places for the sticks from n+k-1 places available; thus the cardinality will be the combinatorial number of n+k-1 with k-1, {n+k-1 \choose k-1} .

For the 2 largest classrooms we distribute n = 50 chairs. Here k = 2, thus the total amount of ways to distribute them is {50+2-1 \choose 2-1} = 51 .

For the 3 remaining classrooms (k=3) we need to distribute the remaining 50 chairs, here we have {50+3-1 \choose 3-1} = {52 \choose 2} = 1326 ways of making the distribution.

As a result, the total amount of possibilities for the chairs to be distributed is 51*1326 = 67626.

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3 years ago
-20 2 -6 -18 4 -4 put them from least to greatest
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-20 -18 -6 -4 2 4 this is the answer
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What is seven square root two
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