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2 years ago

Find the ratio of triangles to circles in the diagram below

Mathematics

1 answer:

Sedaia [141]2 years ago

7 0

Answer:

Ratio should be equal so ratio is 3:3

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MATH!!!

kozerog [31]

Answer:

210 Hope it helps! if you have any other questions I can help

6 0

2 years ago

Consider these three squares with known area 25, 144,169

hram777 [196]

Answer:

Step-by-step explanation:

three squares with known area 25, 144,169...

1) area of the square =25

Side ×side=25

Side^2=25

Side=√25

Side =5.

Answer is 5.

2) area of the square =144

Side ×side=144

Side^2=144

Side=√144

Side =12

Answer is 12.

3)area of the square =169

Side ×side=169

Side^2=169

Side=√169

Side =13

Answer is 13.

6 0

3 years ago

Which line is perpendicular to the line y=-1/3x-2 and passes through point (1,4)

xxMikexx [17]

Answer:

Option 3) y = 3x+1

Step-by-step explanation:

Given equation is:

y = $-\frac{1}{3} x -2$

Perpendicular => It will have a slope of negative reciprocal to this slope

So the ⊥ line has a slope = m = 3

Now,

Point = (x,y) = (1,4)

So, x = 1, y = 4

Putting this in slope intercept form to get b

=> $y = mx+b$

=> 4 = (3)(1) + b

=> b = 4-3

=> b = 1

Now, Putting m and b in the slope intercept form to get the required equation:

=> y = 3x+1

4 0

3 years ago

Read 2 more answers

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$